《c++ 实践之路》光盘中的源代码

C科学工程程序库-C library science project

使用c++编写一个简单的三角形单元有限元程序，通过编译链接，已经可以，初学有限元程序着可以看看

约瑟夫问题的一种描述是：编号为1，2，…，n的n个人按顺时针方向围坐一圈，没人持有一个密码。一开始人选一个正整数作为报数上限值m，从第一个人开始按顺时针自1开始报数，报到m是停止报数。报m的人出列，将他的密码作为新的m值，从他在顺时针方向上的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。-a description of the problem is : No. 1, 2, ..., n n clockwise direction by individuals sitting around a circle, no one holding a password. One person started as a positive integer limits on the number of reported m, from the first individuals to embark on the clockwise from a few reportedly started, the report m is reportedly stopped a few. M reported out of the list of his password as a new value m, from a clockwise direction in the next re-started from a newspaper a few, like that, until the total of all listed so far.

基本算法为：先将1填入第一行中间位置；再依次将2-n方按如下规律填写：//1，填入上个数上一行的右边位置，如果没有上一行则转到最后一行，如果右边没有方格//则转到最左边的方格。2，如果要填的位置上已经有数，则转填到它上一个数的下边方格//3，对于第一行的最后一个数的下一个数应填在该数下边的空格处-basic algorithm : a first Enter the middle of the first line; Another will be followed by 2-n-law filled out as follows :// 1, the number entered on the right side on his position, if not in his will to the last line, if not right box// then transferred to the most left while the box. 2, to fill the position of several, in turn, to fill it on a number of subordinate box// 3, the first trip to the final a few under a few should fill in the blank space of a few top candidate Department

这是VC迷宫的代码，写的很整洁，非常的好，下载了即使可以用，声音什么的没有设置

这是一个利用simpson求积公式来计算近似积分值，精度比较高-This is an advantage of simpson quadrature formula to calculate the approximate integral value, high precision

07高教杯数学建模b题之北京公交车查询系统-07 Higher Education Cup title b Mathematical Modeling of Beijing Bus Inquiry System

用C++编写的三次养条插值算法-prepared custody of the three interpolation algorithm

一个用c语言编写的存储管理模拟程序- The memory management simulator which compiles with the c language

算法 广度优先搜索、深度优先搜索等。 数据结构课程、算法分析内会使用到的有关算法、结构的建立。 包括广度优先搜索、深度优先搜索、广义表、树结构、队列建立等。