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MSP430FG43x系列单片机汇编源代码
MSP430FG43x系列单片机汇编源代码-MCS MSP430FG43x source code compilation
- 2022-01-25 23:20:09下载
- 积分:1
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文章介绍了一种以8031单片机为核心片,外接扩展芯片AT93C46电擦除可编程只读存储单片...
文章介绍了一种以8031单片机为核心片,外接扩展芯片AT93C46电擦除可编程只读存储单片-Article to introduce a 8031 single-chip microcomputer as the core chip, an external expansion AT93C46 chip erase power programmable read-only memory chip
- 2022-04-01 04:33:56下载
- 积分:1
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此程序时周立功ZLG7290源码驱动,这是我开发版上的源码
此程序时周立功ZLG7290源码驱动,这是我开发版上的源码-This program Ligong weeks ZLG7290 source driver, this is my development version of the source
- 2022-01-25 20:16:48下载
- 积分:1
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数据采集PCF8591 A/D由89S52处理LCD显示语言转换…
采集数据经pcf8591的A/D转换由89S52处理在LCD显示出来的代码 C语言编写-Collecting data pcf8591 the A/D conversion by the 89S52 handle LCD display language of the code C
- 2022-03-14 05:59:34下载
- 积分:1
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鉴于MCS
鉴于MCS-51系统只提供“二级中断嵌套”,提出扩展51系统中断优先级的纯软件方法。其利用51系统内建的中断允许寄存器IE和中断优先级寄存器IP,通过屏蔽字机制来实现;以C51的形式,给出这种扩展方法的函数库实现,为该方法的使用赋予友好、简洁的用户接口。-Given MCS-51 systems only provide "two interrupt nesting," expanded 51 priority system interruption of pure software. The use of 51 built-in system allows interruption Register IE and priority interrupt register IP, through word shielding mechanisms to achieve; C51 in the form of this expansion is the way to achieve functions, methods for the use of empowerment friendly, simple user interface.
- 2022-01-26 06:59:29下载
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该程序通过调试,可以实现cc2420收发功能
该程序通过调试,可以实现cc2420收发功能-The program through the debugger, you can realize CC2420 transceiver functions
- 2022-03-12 23:09:02下载
- 积分:1
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ATmega16 PA control population cycle of eight lights lit
控制ATmega16 PA口的8盏灯循环点亮-ATmega16 PA control population cycle of eight lights lit
- 2022-11-04 03:05:04下载
- 积分:1
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MSP430F449的来源,,,很好的总结
msp430f449源程序,, ,很好地总结-MSP430F449 source,,, well summed up
- 2022-03-07 15:51:36下载
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FFT函数C源代码
FFT FUNCTION "C" SOURCE CODE
- 2022-01-26 00:34:35下载
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一维多项式多组求值,利用系数预处理法对多项式p(x)=an
一维多项式多组求值,利用系数预处理法对多项式p(x)=an-1x^n-1+an-2x^n-2+...+a1x+a0,进行多组求值。其中n=2^k-Many one-dimensional polynomial evaluation group, using coefficient polynomial preconditioning method p (x) = an-1x ^ n-1+ an-2x ^ n-2+...+ a1x+ a0, for many Group evaluated. One of n = 2 ^ k
- 2022-01-26 06:39:10下载
- 积分:1