基于Boosting 算法的人脸检测

追赶法求解三对角矩阵是数值算法中重要的一种,这个利用了求借热传导方程-chased solve three-diagonal matrix numerical algorithm is an important, the use of the demand by heat conduction equation

This is the project of my course in the USA: Customers arrive at a service station (with a single server) according to the Poisson process with a mean arrival rate of lambda = 0.3 (customers/min). Each customer waits in queue (if present), proceeds to receive service upon his/her turn, and departs the system when the service is completed. The service time is uniformly distributed between 2.5 and 4.5 minutes. On each day, the service station is open for two hours. Any customers in queue at the end of work hours are served before closing the service station for the day. Use simulation (do 100 simulation runs) to determine

杭州电子科技大学在线系统ACM的1162题，用贪心方法解决-Hangzhou University of Electronic Science and Technology ACM-line system of the 1162 title with a greedy solution

这个程序允许您在 c + + 控制台模式中正方形的面积计算。

应用统计学的线性回归分析-165 linear regression analysis

这是一个数学建模的讲义，很有用的！希望大家能多下载这个，-This is a mathematical modeling of the notes, very useful! I hope everyone can download this,

// 矩阵乘法: C=AB, A[m×v],  B[v×n],  C[m×n] ... for row-major matrices   // 允许A,B,C 带入相同参数. double* matr_x(double*C, const double*Ao, const double*Bo, const int m,const int v, const int n){ if(!Ao || !Bo) return 0;    if(!C) C=new double[m*n];  double* A=new double[m*v], * B=new double[v*n];  memcpy(A,Ao,m*v*sizeof(double)); memcpy(B,Bo,v*n*sizeof(double));  请点击左侧文件开始预览 ！预览只提供20%的代码片段，完整代码需下载后查看 加载中 侵权举报

已经一整数n，求1！+2!+3!+4！+5！+6！+……+n！，n

本程序是例子滤波的一个仿真程序，实现非线性非高斯的例子滤波及预测功能-This program is an example of a simulation program filtering to achieve an example of nonlinear non-Gaussian filtering and prediction

循环链表实现约瑟夫环，并对输入错误进行检查和提示。-cycle Chain achieve Josephus, and input error check and tips.