轮围计算器

这个程序可实现最优二分检索树的构造，绘制和检索，请在Turboc 2.0下运行-this procedure can achieve optimal two-tree structure retrieval, mapping and retrieval, please run Turbo 2.0

用C++实现求解图的边介数，文件中包含.h和.cpp文件，输入文件是txt文件：点的个数以及具体的边，例子请见压缩文件中node.txt。该程序是能够运行成功的，对学习复杂网络的初学者有一定的帮助。

此为基于图像配准的傅立叶变换源代码，已精心调试过，请放心使用.-This is the image registration based on the Fourier Transform source code, has been painstakingly debugging, please rest assured that use.

我们想要使用此算法以解决集装箱装载问题查找最佳对象的最佳选择采取他们在容器中

Turbo Code simulator 用于仿真的源代码和说明文件。-Turbo Code simulator for the simulation of the source code and documentation.

C语言求逆矩阵 介绍一下算法导论上的一般的矩阵求拟算法思路。 假设要对矩阵A求逆，首先利用矩阵论知识，对A进行LUD分解。 利用分解出来的矩阵L，U，D来求解AB=I中的n个线性方程组，得到n个解向量，所有解向

产生泊松分布随机数的程序-generated random Poisson distribution of the process

趣味问题的程序原代码 海滩上有一堆桃子，五只猴子来分。第一只猴子把这堆桃子凭据分为五份，多了一个，这只 　　　猴子把多的一个扔入海中，拿走了一份。第二只猴子把剩下的桃子又平均分成五份，又多了 　　　一个，它同样把多的一个扔入海中，拿走了一份，第三、第四、第五只猴子都是这样做的， 　　　问海滩上原来最少有多少个桃子？- On the interest question procedure original code beach has pile of peaches, five monkeys divide. The first monkey divides into this pile of peach proof five, many, this monkey has thrown into many in the sea, took away. The second monkey the peach which is left over equally divides into five, also many, it similarly has thrown into many in the sea, took away, third, fourth, the fifth monkey all is does this, asked how many peaches on the beach most is originally unusual?

一个费诺编码器,输入N个总和为1的小数,就可以得到N个费诺码-a fee Connaught encoder input N sum of a minority, it can be N Connaught yards charges

用传输矩阵方法编写的matalb程序，可以用来计算透射率与缺陷折射率之间的关系-Transfer matrix method used to prepare the matalb procedures, can be used to calculate the transmission rate and defects in the refractive index of the relationship between