linux下串口驱动！ 不错，可以看一看！了解串口的驱动！

是一个用isual C++写的基于串口的手机通信程序，希望对大家有用。-Is a use isual C++ Written in mobile phone based on the serial communication program, in the hope that useful to everyone.

4510 bios,please see it carefully!and so on,no thanks

通过串口发送at指令 等待返回值判断当前的网络状况以及服务商等有关信息 用与gprs的通信-sent through the serial port at the value orders waiting to return to judge the current state of network service providers and other relevant information in communications with EDGE

参加一竞赛的程序(我负责的部分)，包括STH11温湿度传感器的驱动，一般模拟传感器的串口通信-participate in a contest (my part), including STH11 temperature and humidity sensor-driven, Sensor Simulation general Serial Communication

wavecom短信猫使用源代码及相关AT指令-Wavecom message cat use the source code and related AT commands

该程序是实现蓝牙串口通信的，在计算机上用vb进行编程，打开蓝牙的uart口，从而打开蓝牙的串口。-Bluetooth serial communications, computers programmed with vb, Bluetooth UART open mouth, open the Bluetooth Serial Port.

〈VC++串口通讯技术〉一本很不错的介绍PC串口通讯技术的书- A very good introduction to the book PC serial port communication technology

93c46-24c.rar look read rw-93c46-24c.rar

getmywish结合visual basic60和msdn帮助，编写了一个两个串口的受到发送程序，该程序在win98,win2000,winxp下调试通过，希望和大家工勉-getmywish combine visual and VARIANT basic60 help prepared a two Serial sent by the program, which in win98, WIN2000. Debugging under winxp passed, and we hope that the Mian

这是非常有挑战性的题目。对于用户输入的任意一个平面函数f(x)，绘制出其函数曲线。这里最关键的技术难点就是如何实现计算表达式的值。在《编译原理》和《数据结构》的书中，都有对表达式运算方法的论述。说实在的，在编译型计算机语言中实现对用户输入表达式的运算是非常困难的。需要对表达式进行扫描，去括号，按照运算符的优先级生成2叉树，然后遍历该树生成逆波兰表达式，再然后通过栈的方法进行运算。如果在表达式中再包含有函数的话......描述起来都麻烦，更不要说用程序实现了:-(-This is a very challenging issue. For user input an arbitrary planar function f (x), mapping out its function curves. Here the most critical technical problems is how to achieve calculated the value of the expression. "Compiling Principle" and "data structure," the book, have right of expression Operational discussed. Indeed, the computer language compiler to achieve expression of the user input operation is very difficult. Need to scan expression to the brackets, in accordance with the priority Operators Generation 2-ary tree, and then traverse the tree generated reverse Polish expression, and then through the stack approach to computing. If the expression again contains the function described ...... these are trouble, not to mention t