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In a weighted directed connected graph G, given the starting point v, find it to...
在一个带权有向连通图G中,给定出发点v,求出它到所有点的最短路径长度-In a weighted directed connected graph G, given the starting point v, find it to all points of shortest path length
- 2023-06-27 23:45:03下载
- 积分:1
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与CI的DTMF解码阶段它应该工作
dtmf decoder with ci itegrated it should work
- 2022-02-20 10:35:03下载
- 积分:1
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源码就如何自定义异常抛出做了一定的阐述。希望对大家有用...
源码就如何自定义异常抛出做了一定的阐述。希望对大家有用-Source on how to make custom exception thrown out of some. Everyone would like to be useful
- 2022-05-30 07:12:33下载
- 积分:1
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ripple addrr
好的一个vhdl代码的纹波进位加法器好的一个vhdl代码的纹波进位加法器
- 2022-03-29 03:56:10下载
- 积分:1
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ssd4exercise5的作业答案,欢迎你的下载,谢谢了
ssd4exercise5的作业答案,欢迎你的下载,谢谢了-Operating ssd4exercise5 the answer, you are welcome to download, I would like to thank the
- 2023-03-18 05:15:03下载
- 积分:1
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CrossTheMaze
Assume that Edison has found himself in a square-shaped maze of NxN square cells which is surrounded by walls from the outside. In the maze, some of the cells are also walls. Edison can only move between two empty cells in four directions, north, south, west and east. In order to get out of the maze, he drafts a plan. He uses his left hand to lean on the wall and goes by following the wall.
Here is the question, is Edison able to get out of the maze in at most 10,000 steps? If he can make it, output the path. By getting out of the maze, he only needs to be in the exit cell. If the starting cell is the same as the exit, Edison won"t need to move and can directly get out of the maze.
Input
The first line of the input gives the number of test cases, T. T test cases follow. Each test case starts with an integer N. N is the size of the maze. Th
- 2022-02-25 06:08:30下载
- 积分:1
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use dial
利用ras写的ADSL拨号程序,该程序能按用户设定的时间进行拨号,能显示拨号后的IP,当然,该软件写得粗浅,只能作为初学者的参考,有达人修改,请寄我一份,luozehui@hotmail.com,谢谢!-use dial-up ADSL written procedures, the procedures can be set by users of dial-up time. Dial-up can show that the IP, of course, the software written shallow and could only serve as reference for beginners, to be revised, I should be sent to a, luozehui@hotmail.com, thank you!
- 2022-03-18 20:06:23下载
- 积分:1
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C++编程的一些源代码,程序都很经典,请大家下载。
C++编程的一些源代码,程序都很经典,请大家下载。-C++ Some programming source code, the procedure is very classic, please download the U.S..
- 2023-08-11 08:20:05下载
- 积分:1
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VOD practical tool that can MPG document, separate video and audio, video compre...
VOD实用工具,可以从MPG文件之中, 分离视频和音频, 视频直接压缩保存DIV5格式, 音频直接保存为WAV格式, 支持双音轨 必须预先安装DSHOW组件 (AX文件:REGSVR32 /C /S [FILENAME].AX) -VOD practical tool that can MPG document, separate video and audio, video compression preservation DIV5 direct format, audio stored directly to WAV format, and supports dual-track must be pre-installed DSHOW components (AX documents : gating/C/S [FILENAME]. AX )
- 2022-01-24 14:55:19下载
- 积分:1
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检测电脑中的HID设备的数量和信息
本程序基于MFC界面开发,使用编程语言C++,编程工具室VS2008,通过按下按钮,可自动检测连接到电脑上的HID设备以及相关的HID设备的信息,该工程需要在工程属性中添加testUSB文件中的头文件,在link中增量链接使能需要改为NO
- 2022-01-22 13:40:23下载
- 积分:1