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汇编语言与设计 我们可以这样的做一些有用的汇编程序
汇编语言与设计 我们可以这样的做一些有用的汇编程序-assembly language and design we could do some useful compilation proce
- 2022-01-22 02:53:18下载
- 积分:1
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基于STC5410单片机AD功能模块测试
基于STC5410单片机AD功能模块测试-Based on test STC5410AD
- 2022-09-15 22:10:03下载
- 积分:1
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带液晶显示屏的1拖8的EEPROM抄写器原代码,抄写速度很快,带校验功能.
带液晶显示屏的1拖8的EEPROM抄写器原代码,抄写速度很快,带校验功能.-LCD screen with one of the 8 trailers EEPROM device copying the original code, copying fast, with calibration function.
- 2022-03-24 20:08:31下载
- 积分:1
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8255的汇编程序,各种工作方式尽有,是初学者学习的好帮手,也是利用8255扩展IO的普遍方法,只用改下地址直接拿去用就行...
8255的汇编程序,各种工作方式尽有,是初学者学习的好帮手,也是利用8255扩展IO的普遍方法,只用改下地址直接拿去用就行-8255 compilation of procedures, a variety of working methods have to do is a good helper for beginners to learn, but also the use of 8255 to expand the universal method of IO only change taken directly under the address used on the line
- 2022-04-08 17:38:18下载
- 积分:1
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编译的c++原代码
编译的c++原代码-the original code
- 2022-02-06 08:36:28下载
- 积分:1
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Ti omap1510的bootloader。多同仁们多交流交流。
Ti omap1510的bootloader。多同仁们多交流交流。-Ti omap1510 the bootloader. Tongren have more exchanges and more exchanges.
- 2022-01-25 14:59:29下载
- 积分:1
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integer function for the two majors and the least common multiple source files
函数求两个整数的最大公约数和最小公倍数的源程序-integer function for the two majors and the least common multiple source files
- 2022-03-04 00:37:23下载
- 积分:1
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单门读卡控制器的 设计程序,主要对em读卡机的设计提供可靠的 资料。...
单门读卡控制器的 设计程序,主要对em读卡机的设计提供可靠的 资料。-Single door reader controller design process, mainly em card reader designed to provide reliable information.
- 2022-12-21 12:50:03下载
- 积分:1
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Principle of Microcomputer experimental procedures, including 8255,8253,8259
微机原理实验的程序,包括8255,8253,8259-Principle of Microcomputer experimental procedures, including 8255,8253,8259
- 2022-08-10 09:33:45下载
- 积分:1
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c语言编译的计算器
为了方便了解流程,在程序中把计算过程也输出了.而且栈操作的实现部分也是自己实现的.
程序用两个栈,optr寄存运算符,opnd寄存操
c语言编译的计算器
为了方便了解流程,在程序中把计算过程也输出了.而且栈操作的实现部分也是自己实现的.
程序用两个栈,optr寄存运算符,opnd寄存操作数和运算结果.输入的表达式以等号结束,例如:2*(1+2)=
-c language compiler of the calculator in order to facilitate the understanding of flow, in the procedure to calculate the output of the process. but Stack is the realization of part of their realization. procedures with two stacks, optr storage operator, opnd operand storage and computing the results of . enter the expression in order to equate the end of, for example: 2* (1+ 2) =
- 2022-10-25 02:00:03下载
- 积分:1