Visual Basic课程举例 2 有很好的例题

详细设计的目的就是指导编码,明确的说,就是将你的设计拿给不同的人去写编码，写出来的程序处理流程相同.后续的评审或者是有人接替你的工作，只要查看详细设计，就能清楚你当时是怎样设计这些流程的。-The purpose is to guide the detailed design codes, specifically, is that your design showed that different people to write code, written procedures for processing the same. Follow-up assessment or someone to replace your job, as long as View the detailed design, we can clearly understand how did you design these processes.

实验器材: 阿波罗STM32F429开发板 实验目的: 学习GPIO作为输出的使用 硬件资源: 1,DS0(连接在PB1)  2,DS1(连接在PB0) 实验现象: 本实验通过代码控制开发板上的两个LED：DS0和DS1交替闪烁，实现类似跑马灯的效

本组程序包括FPGA程序，固件程序和上位机程序，实现USB的数据传输功能，采用Slave Fifo模式，上位机程序利用Cypress公司提供的库函数进行开发-In this group include FPGA, firmware, procedures and PC procedures realize USB data transfer function, the Slave Fifo mode, host computer program using Cypress library functions provided by the company to develop

一个小的教学软件，用来观察三角形面积和边长的关系。-a small educational software, to observe triangle area and side length relationship.

astar算法的改进，很有用，运行没有错误，又需要的同学赶紧下哦-astar algorithm improvements, useful, run no errors, but also those students in need under the oh hurry

本程序将完成印章的制作,与导出,同时可以根据用户需要制定不能大小的图形-This procedure will be completed seal production, and export, at the same time users need to be developed in accordance with the size of graphics should not

dct域内视频的上采样了，640*480到1920*1080-This is a program of video upsample in the dct domain which convert the video resolution from 640*480 to 1920*1080.

DFA的“语言”是这个DFA接受的所有的串的集合。假设a1a2…an是输入符号序列，让这个DFA从初始状态q0开始运行。查询转移函数δ，比如说δ(q0,a1)=q1，以找出DFA在处理了第一个输入符号a1之后进入的状态。处理下一个输入符号a2，求δ(q1,a2)的值，假设这个状态是q2。以这种方式继续下去，找出状态q3,q4,…,qn，使得对每个i，δ(qi-1,ai)=qi。如果qn属于F，则接受输入a1a2…an，否则就“拒绝”。-DFA" s " language" is the DFA to accept all of the string collection. A1a2 ... an assumption is an input symbol sequence, so that the DFA into operation from the initial state q0. Look transfer function δ, say δ (q0, a1) = q1, in order to identify the DFA in dealing with the first input into the state after the symbol a1. To the next input symbol a2, seeking δ (q1, a2) values, assuming that this state is q2. Continue in this way to find out the state q3, q4, ..., qn, making for every i, δ (qi-1, ai) = qi. If qn belongs to F, then accept the input a1a2 ... an, otherwise, " refuse."

windows2008本地安全策略设置，服务的禁用与启用，windows2008系统自动登陆，改运程桌面的商品号。