一个数据源，我们希望鼓励，你下载

我编的一个vb写的管理系统-I wrote a vb Management System

比较准确的进行相机标定，基于OpenCV的摄像机标定程序，实现了摄像机内参数、畸变系数等参数的求取，程序上手简单，通俗易懂，效率较高，适合新手入门。

策略模式vc源码实例。-example vc code of strategy

日志客户端，通用的日志模块。可以提供多个应用程序同时记录一个日志，分模块、分进程、分线程，区别日志。-log client, a common log module. It provides a wide range of applications recorded a log, modular, sub-processes, sub- threads, and between log.

高校人事管理系统实现添加删除修改查看等功能-实现添加删除修改查看等功能

这是关于一个3d的示例，是使用java写的，大家可以看以下，写的一般，请指正，多谢谢了啊-This is a 3d example is the use of java was made, we can look at the following, writing in general, please correct, the more thank ah

本程序实现了一次时间变换等操作。可以计算运行VC 6.0CONST程序下提供的运行时间类别

read from .dat files and show it in plot

分形算法与程序设计VC版的好书，值得推荐哟，欢迎下载!-fractal algorithms and program design VC version of the books recommend yo welcome to download!

还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected