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1一个最优美的图案。
2有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数...
1一个最优美的图案。
2有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数-1 One of the most beautiful designs. 2 months integer n to the preceding number of the order of backward-shift position m, and finally the number m of m into the top of the number of
- 2022-05-05 15:57:46下载
- 积分:1
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Vigenere Cypher
Vigenere Cypher - C Implementation-Vigenere Cypher- C Implementation
- 2022-04-10 03:07:04下载
- 积分:1
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一个多任务的控制软件,可以设置多个任务,时定关机、关闭显示器、重启、待机、打开文件、关闭进程、播放音乐等。...
一个多任务的控制软件,可以设置多个任务,时定关机、关闭显示器、重启、待机、打开文件、关闭进程、播放音乐等。-A multi-mission control software, you can set up a number of tasks, when the scheduled shutdown, turn off monitor, restart, standby, open the file, close the process, such as playing music.
- 2022-01-21 06:09:24下载
- 积分:1
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最新的pkcs11 密码令牌接口标准 费了很大的劲才找到的
最新的pkcs11 密码令牌接口标准 费了很大的劲才找到的
-Latest PKCS11 password token interface standard costs a lot of劲才found
- 2022-01-31 21:12:32下载
- 积分:1
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ncc_tetrahederon是Fortran90库定义的权重和abscisass…
Newton-Cotes积分公式的加权系数计算程序库。用Fortran90编写。-NCC_TETRAHEDERON is a FORTRAN90 library which defines the weights and abscisass for a sequence of 7 Newton-Cotes closed quadrature rules for the tetrahedron.
- 2022-03-19 10:19:10下载
- 积分:1
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vb_net_rs232.zip vb_net_rs232.zip
vb_net_rs232.zip vb_net_rs232.zip-vb_net_rs232.zip vb_net_rs232.zip vb_net_rs232.zip
- 2022-12-07 08:15:03下载
- 积分:1
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在windows程序中读取bios内容,对你挺有帮助,能够见识到bios方面的内...
在windows程序中读取bios内容,对你挺有帮助,能够见识到bios方面的内-the windows proceedings read bios, you quite right help, to see that within the bios
- 2023-07-17 01:55:03下载
- 积分:1
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孙鑫老师VC++Lesson17进程间通信,可以自由下
孙鑫老师VC++Lesson17进程间通信,可以自由下-SUN Xin teachers VC++ Lesson17-process communication, they can under the
- 2022-05-18 23:11:44下载
- 积分:1
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应用银行家算法解决死锁问写的银行家算法,只能实现固定进程和资源的操作,不过要是应付作业什么的没有问题,绝对可以运行...
应用银行家算法解决死锁问写的银行家算法,只能实现固定进程和资源的操作,不过要是应付作业什么的没有问题,绝对可以运行 -application bankers algorithm to solve the deadlock was asked bankers algorithm, the process can only be fixed and operational resources, but what if the deal with no operational problems and it can definitely run
- 2022-02-16 01:52:18下载
- 积分:1
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public class gedebahe { public static void main( String [] args) { for ( ) { int...
public class gedebahe { public static void main( String [] args) { for ( ) { int a=-1,b,c //b,c是分解出来的两个数 System.out.print("Please input a oushu:") //输入一个偶数 try { BufferedReader in = new BufferedReader(new InputStreamReader(System.in)) String inputLine = in.readLine() a = Integer.valueOf(inputLine).intValue() }catch (Exception exc) { System.out.println("Sorry,please input a number.") return } if (a%2!=0) { System.out.println("Sorry,please input a oushu.") return } for (b=1 b
- 2022-09-15 17:45:03下载
- 积分:1