雅可比迭代解线性方程组 这个也是计算方法中另一种 求解线性方程组的计算程序...

应用背景Massive multiuser MIMO (MISO): ◮ M ≫ K ≫ 1 (think 100 × 10 or 500 × 50) ◮ coherent, but simple, processing ◮ Potential to dramatically improve rate & reliability ◮ Potential to drastically scale down TX power ◮ Not only theory, at least one known testbed (64× ∼10) 关键技术 Massive MIMO Operation Not enough resources for pilots & CSI feedback, so operate in TDD. ◮ On the uplink, ◮ acquire CSI from uplink pilots and/or blindly from data ◮ detect symbols ◮ M ≫ K ⇒ linear processing (MRC, ZF, MMSE) nearly optimal ◮ On the downlink, ◮ use CSI obtained on the uplink ◮ make necessary adjustments based on reciprocity calibration ◮ apply multiuser MIMO precoding ◮ simple precoders desirable (and very good!): MRT, ZF, MMSE, ... ◮ MRC/MRT operation ◮ intracell interference will appear as

应用背景 这是一个用计算机图形学做的的二维绘图程序，界面良好，互动性高。主要内容包括：1.基础图元的生成，如直线、椭圆、区域填充等。 2.样条曲线的生成，如Bezier曲线、B-样条曲线，二次累加 弦长曲线。3.任意的多边形的生成。 关键技术 MFC的框架。onpaint函数编写。二次曲线的算法。任意多边形生成算法。

VC++实现的二分法求单调函数是否有解。-VC++ dichotomy in order to achieve the monotonic function is broken.

c++数组。一维数组的插入，删除，排序-c array. One-dimensional arrays of the insert, delete, sort, etc.

kalman算法以及里面用到的矩阵运算，包括kalman filter extended kalman filter iterated extended kalman filter-kalman algorithm and used inside the matrix operations，a kalman filter, an extended kalman filter, and an iterated extended kalman filter

this to find out the shortest path for various nodes-this is to find out the shortest path for various nodes

这是一个超长整数加法.转载.-This is a long integers. Reprinted.

应用背景扫描枪在扫描货品条码时，虽然可以在电脑上显示出扫描到的数字，但是不能显示条码图片。我们在应用的过程中可能需要将条码一起打印出来显示在一张A4纸上。所以可以利用这个类生成相应的128条形码图片，然后插入到word中，并将相应的条码（包含条码图形）打印出来。这类应用在仓库管理中应用较多，比如要把一个货架上的所有箱码打印显示在A4纸上。然后扫描枪只要扫描这张纸上的条码就可以知道这个货架上有哪些货。关键技术代码的核心是它将128码的码制定义在一张DataTable表中，这个表中记录了每个数字和字母对应的条形码编号，用这些编号来生成条形码。比如你给一串数字，要生成一个条形码时，代码会取出这串数字每个数，然后查询这张表格，记录每个数在表格中对应的位置。这些索引形成一个list，然后根据这个list生成一个bimap,最后保存为图片。

The Canny edge detector is an edge detection operator that uses a multi-stage  请点击左侧文件开始预览 ！预览只提供20%的代码片段，完整代码需下载后查看 加载中 侵权举报

设A和B是2个字符串。要用最少的字符操作将字符串A转换为字符串B。这里所说的字符操作包括： 1. 删除一个字符 2. 插入一个字符 3. 将一个字符改为另一个字符 将字符串A变换为字符串B所用的最少操作数称为A到B的编辑距离，极为d(A,B)。设计一个算法，计算任意两个字符串的编辑距离。 -Set A and B are two strings. Operation will use the least character string A is converted to a string B. Operation of characters are talking about here include: 1. Delete a character 2. Insert a character 3. Will be replaced by one character to another character will be transformed into a string A string of at least B operand used by A to B is called the edit distance is extremely d (A, B). Design an algorithm to calculate any two of the string edit distance.