登录
首页 » Windows开发 » The system functional requirements: Suppose Student Information includes: Stude...

The system functional requirements: Suppose Student Information includes: Stude...

于 2022-03-16 发布 文件大小:1.62 kB
0 206
下载积分: 2 下载次数: 1

代码说明:

系统功能需求: 假设学生信息含有:学号、姓名、成绩。要求用单链表表示一个班的学生信息,并能用菜单形式实现如下功能(菜单要能重复使用): 1、建立单链表 2、输出单链表 3、查找单链表 4、插入单链表 5、删除单链表 6、更新单链表 7、逆置单链表 0、退出系统 -The system functional requirements: Suppose Student Information includes: Student ID, name, performance. Require a single linked list, said the students information, and can be used to achieve the following functions form the menu (menu to be able to re-use): 1, the establishment of a single linked list 2, the output single-linked list 3, to find a single linked list 4, insert a single linked list 5, to delete a single linked list 6, update a single list 7, reverse a single linked list home 0, exit the system

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • 面向点集的实体模型重构
    Reconstruction of Solid Models from Oriented Points Sets
    2023-01-15 19:10:03下载
    积分:1
  • a process sequence, the small software (vc)
    产生程序序列号的小软件(vc++)-a process sequence, the small software (vc)
    2023-03-13 02:00:04下载
    积分:1
  • its a whole of documents related to energy efficient routing protocols
    its a whole of documents related to energy efficient routing protocols
    2022-01-31 10:49:29下载
    积分:1
  • Matrix
    矩阵相关运算,拷贝矩阵,打印矩阵内容,为矩阵赋初值,调用高斯约旦算法求逆矩阵-Matrix-related operations, matrix copy, print the contents of the matrix for the matrix given initial value, called Gauss Jordan matrix inversion algorithm
    2022-02-12 12:14:56下载
    积分:1
  • 书中的一个经典实例,在此摘录出来,让C++此方面编程的朋友可以更容易的找得到,压缩包内有3种识别技术的算法实例,需要慢慢研究哦。...
    书中的一个经典实例,在此摘录出来,让C++此方面编程的朋友可以更容易的找得到,压缩包内有3种识别技术的算法实例,需要慢慢研究哦。-A classic example of the book, in this excerpt from, let C++ This regard programming friends can more easily find, compressed packet, there are three kinds of algorithm to identify examples of technologies, the need to study slowly Oh.
    2022-01-31 08:57:09下载
    积分:1
  • 2.4G无线通信实验+光电采集计数
    实现了光电计数器的2.4G射频传输。采用开发板stm32f103zet6。使用库函数分装。实现了光电计数器的2.4G射频传输。采用开发板stm32f103zet6。使用库函数分装。实现了光电计数器的2.4G射频传输。采用开发板stm32f103zet6。使用库函数分装。实现了光电计数器的2.4G射频传输。采用开发板stm32f103zet6。使用库函数分装。
    2022-04-10 05:38:27下载
    积分:1
  • 插入IE穿墙下载者 过大多数杀软 防火墙
    插入IE穿墙下载者 过大多数杀软 防火墙-dll inserted downloader through fire walls and the majority of anti-virus
    2022-06-16 15:53:32下载
    积分:1
  • lift detection system to lift performance testing system. It is a learning proce...
    电梯检测系统是对电梯性能进行检测的系统。是一个用来学习的程序-lift detection system to lift performance testing system. It is a learning process for
    2022-02-21 17:14:57下载
    积分:1
  • function [tout, yout] = rk4 (ypfun. tspan, y0, h)% fixed step four
    function [tout, yout] = rk4(ypfun, tspan, y0, h) %定步长四阶Runge-Kutta法求常微分方程(组)数值解 %[tout,yout] = rk4( ypfun , tspan, y0,h) % 这里字符串ypfun是用以表示f(t, y)的M文件名, % tspan=[t0, tfinal]表示自变量初值t0和终值tf % y0表示初值向量y0,h是步长。 % 输出列向量tout表示节点 (t0 , t1 , … , tn) % 输出矩阵yout 表示数值解,每一列对应y的一个分量-function [tout, yout] = rk4 (ypfun. tspan, y0, h)% fixed step four-stage Runge- Kutta method for ordinary differential equations (Group) numerical solution% [tout. yout] = rk4 (ypfun, tspan, y0, h)% string ypfun here is used to indicate that f (t, y) M name, tspan% = [t0. tfinal] said variable initial and final t0 tf% y0 said initial vector y0, h is a step. % Output column vector tout said Node (t0, t1, ..., tn)% output matrix yout said numerical solution, each y counterparts out of a weight
    2023-01-15 01:20:03下载
    积分:1
  • dynamic two
    动态二维数组的c++模板函数实现,实现了动态创建一维和二维数组,资源清除。-dynamic two-dimensional array of c template function, has implemented a dynamic creation of a dimensional and two-dimensional array of resources to remove.
    2022-02-09 14:34:36下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载