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C# 实现串口超级终端 能发送文件
c# 实现的串口超级终端程序。能设置串口参数,并能保存;自动扫描计算机上的所有串口,并以列表形式显示;能设置显示字体和颜色,并能保存,下次打开默认上次的设置。
- 2022-03-19 19:26:30下载
- 积分:1
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Bezier曲线
Bezier曲线的算法生成基于vc++的实现 -Bezier curve-based algorithm vc++ Realize the
- 2022-02-14 22:10:02下载
- 积分:1
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这个程序是创建XML文件
这个程序是创建XML文件-The program is the creation of XML documents
- 2022-02-25 23:18:51下载
- 积分:1
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一本难得的书,学习C++的必备书籍,我们建议教师。
一本难得的好书,学习C++必备的书籍,我们老师上课推荐。-A rare book, learning C++ Required books, we recommend teacher.
- 2022-02-04 06:27:44下载
- 积分:1
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DIALUP(拨号网络)
资源描述说明:使用 Windows95 拨号网络及远端存取服务 ( Remote Access Service ) 构件 ( 1.31 版,附源码 )
- 2022-12-22 01:45:04下载
- 积分:1
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快速表格的演示程序,或许正是你所需要的呢?演示qucik grid
快速表格的演示程序,或许正是你所需要的呢?演示qucik grid-rapid form of demonstration program, perhaps you need? Qucik grid demo
- 2022-04-11 17:13:54下载
- 积分:1
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菜单和加速键编程的例子
菜单和加速键编程的例子-menu and accelerate key programming examples
- 2023-06-18 13:35:03下载
- 积分:1
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串口数据通信,能直接从PC机串口上获得数据且显示出来
串口数据通信,能直接从PC机串口上获得数据且显示出来-Serial data communications, directly from the PC serial port on the machine and display data
- 2022-03-05 03:48:51下载
- 积分:1
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sniffer 网络工具,够能对IP数据包及时捕获。并能识别出tcp,ip,udp等...
sniffer 网络工具,够能对IP数据包及时捕获。并能识别出tcp,ip,udp等-a sniffer network tool which can capture the IP data pack timely, can identify tcp,ip,udp etc.
- 2023-02-22 03:20:03下载
- 积分:1
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约瑟夫环(Joseph)问题的一种描述是:编号为1,2,…,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始人选一个正整数作为报数上限值m,从...
约瑟夫环(Joseph)问题的一种描述是:编号为1,2,…,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始人选一个正整数作为报数上限值m,从第一个人开始按顺时针方向自1开始顺序报数,报到m时停止报数。报m的人出列,将他的密码作为新的m值,从它在顺时针方向的下一个人开始重新从1报数,如此下去,直至所有人全部出列为止。试设计一个程序求出出列顺序-Joseph Central (Joseph) a description of the problem is: numbered 1,2, ..., n of n individuals according to a clockwise direction around a circle, each holding a password (positive integer). The beginning of a positive integer as a candidate at a number of upper limit of m, from the first individual to embark on the clockwise direction since the beginning of the order of 1 is reported the number of stops required to report back at a few m. Those who reported m out of his password as the new value of m, in a clockwise direction from the next person to start off again from the 1, and so on, until all that out until all. Try to design a procedure to derive the column order
- 2022-02-10 01:58:28下载
- 积分:1