JPEG压缩编码系统源代码

根据图斑错误画圆程序处理得到的CAD表文件，读取其中的坐标并在CAD下画圆。-According to the error Circle Polygon procedures get CAD table file, read one of the coordinates and draw a circle under the CAD.

是在C编程环境下的玫瑰图形源程序。-is in the C programming environment Rose graphics source.

DIB(Device-indepent bitmap)的与设备无关性主要体现在以下两个方面： DIB的颜色模式与设备无关。例如，一个256色的DIB即可以在真彩色显示模式下使用，也可以在16色模式下使用。 256色以下(包括256色)的DIB拥有自己的颜色表，像素的颜色独立于系统调色板。 由于DIB不依赖于具体设备，因此可以用来永久性地保存图象。DIB一般是以*.BMP文件的形式保存在磁盘中的，有时也会保存在*.DIB文件中。运行在不同输出设备下的应用程序可以通过DIB来交换图象。 DIB还可以用一种RLE算法来压缩图像数据，但一般来说DIB是不压缩的。 DIB的结构-DIB (Device-indepentent bitmap) has nothing to do with sexual equipment mainly in the following two aspects : DIB color mode has nothing to do with the equipment. For example, a 256-color DIB is the true color display mode, or can be used in 16 color mode. 256-color below (including 256 colors), the DIB has its own color table, color of the pixel independent system palette. As DIB is not dependent on specific equipment, it can be used for permanent preservation of images. DIB normally*. BMP file stored in the form of disk, sometimes stored in*. DIB document. Running on different output devices under the application of the procedure can be DIB to exchange images. DIB can also use a RLE compression algori

Visual C++/DirectX9 3D游戏开发引导的一个基于视点相关的LOD地形渲染-Visual C++/DirectX9 3D game development as a guiding view-dependent LOD-based terrain rendering

图片格式GIF解码函数库，由于是ASM，速度非常快。-decoding functions, as is ASM, very fast.

直线扫描算法rivate AX1(100) As Integer, AY1(100) As Integer, AX2(100) As Integer, AY2(100) As IntegerPrivate CX1 As Integer, CY1 As Integer, CX2 As Integer, CY2 As Integer, N As IntegerPrivate Sub form_Load()Picture1.BackColor = RGB(255, 255, 255)N = 0End SubPrivate Sub picture1_MouseDown(Button As Integer, Shift As Integer, X As Single, Y As Single)If Button = 1 ThenCX1 = CInt(X): CX2 = CInt(X)CY1 = CInt(Y): CY2 = CInt(Y)End IfEnd Sub-linear scanning algorithm rivate AM1 (100) As Integer, AY1 (100) As Integer, AX2 (100) As Integer, AY2 (100) As IntegerPrivate CX1 As Integer, CY1 As Integer, CX2 As Integer, CY2 As Integer, N As IntegerPrivate Sub form_Load () Picture1.BackColor = RGB (255, 255, 255) N = 0End SubPrivate Sub picture1_MouseDown (Button As Integer, Shift As Integer, As Single X, Y As Single) If Button = = a ThenCX1 CInt (X) : CX2 = CInt (X) = CY1 CInt (Y) : CY2 = CInt (Y) End Sub IfEnd

基于颜色直方图的方法以上是具体实现设想，程序实现如下-Color histogram-based method is more than the specific implementation is envisaged that implementation procedures are as follows

MATLAB动画源代码，可稍加调试后运行，精简代码-failed to translate

基于别人框架实现直方图的交集图像检索 本人感觉要比其颜色矩和分块直方图的要更优一些，在此对其框架表示感谢-others based framework to achieve the intersection histogram image retrieval, I feel than its color moments and the block to the histogram better, in which framework expressed their gratitude

一个用DELPHI写的生成验证码的东西,很有用-DELPHI written with a Verification Code to generate something useful