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还是一个asm编的VXD例子
还是一个asm编的VXD例子-asm or a series of examples VXD
- 2023-04-16 10:35:03下载
- 积分:1
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51编写的电扇的程序,可以控制转速,并且在液晶上显示。在我们的板子上可以调试通过的...
51编写的电扇的程序,可以控制转速,并且在液晶上显示。在我们的板子上可以调试通过的-51 fans prepared procedures to control speed, and liquid crystal display. In our board can debug through the
- 2022-11-23 07:25:03下载
- 积分:1
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RX8025时钟芯片操作程序,初始化时钟,写时间等,用汇编(ASM)编写!...
RX8025时钟芯片操作程序,初始化时钟,写时间等,用汇编(ASM)编写!-RX8025 clock chip operating procedure, initialize the clock, the time to write, using the compilation (ASM) to prepare!
- 2022-03-16 05:33:37下载
- 积分:1
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此文件应用PIC16F913实现LCD控制,本程序具有加,移,设置三键功能,可以在仪器仪表等方面应用....
此文件应用PIC16F913实现LCD控制,本程序具有加,移,设置三键功能,可以在仪器仪表等方面应用.-Application of this document PIC16F913 realize LCD control, this procedure has the added, changed, set three key features, such as in the application of instrumentation.
- 2022-05-25 13:16:47下载
- 积分:1
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本公司高人设计的程序的头部分,很经典,原程序有2万多行
本公司高人设计的程序的头部分,很经典,原程序有2万多行-Expert design of the Company during the first part of the procedure, it is classic, the original procedures are more than 20,000 line
- 2022-11-16 12:15:03下载
- 积分:1
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压缩文件包含类型d1e Award BIOS的源代码,支持的特征。
AWARD BIOS源代码,支持的CHIPSET请看文件,有同型号的板子烧上去就可以跑-the compressed file contains the source code of AWARD BIOS type D1E.Supported chipsets are listed in the related file.One can complie,download and run it on the mainboard if he has such one.
- 2022-02-22 01:57:55下载
- 积分:1
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masm old fargon 2 to do asmbly code
masm old fargon 2 to do asmbly code
- 2022-12-15 09:55:02下载
- 积分:1
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JAVA study into primary, textbooks code calculation and the procedure code conve...
JAVA学习初级变成,课本代码 有关程序计算和代码换算-JAVA study into primary, textbooks code calculation and the procedure code conversion
- 2022-07-11 08:16:44下载
- 积分:1
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verilog写的分频程序,可以对输入的频率分频
verilog写的分频程序,可以对输入的频率分频-Verilog write the sub-frequency procedures, can the frequency of the input frequency
- 2023-08-11 09:50:04下载
- 积分:1
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学生成绩核算系统的设计与实现(25)
要求:(1)按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。
(2)三个成绩对总评成绩的百...
学生成绩核算系统的设计与实现(25)
要求:(1)按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。
(2)三个成绩对总评成绩的百分比被定义为常数,各占总成绩的30 、30 和40 。
(3)计算每位学生的总评成绩。
(4)计算该班级本课程的总平均成绩。
(5)计算处于优、良、中、及格、不及格的学生人数以及占总人数的百分比。其中100-90为优,89-80为良,79-70为中,69-60为及格,60分以下为不及格。
(6)按要求输出成绩在优、良、中、及格、不及格各区间的学生学号、成绩。-The student achievement calculation system s design with realizes (25) Request: (1) reads in the corresponding usual result, the midterm examination result and the terminal examinations result according to the class and grade according to the curriculum from the document. (2) three result are defined to the general appraisal result s percentage as the constant, occupies the overall result respectively 30 , 30 and 40 . (3) calculates each student s general appraisal result. (4) calculates this class and grade this curriculum the population mean result. (5) calculates the student population which is in superiorly, good, passes an examination, does not pass an examination as well as accounts for the total number of peop
- 2022-05-25 02:22:21下载
- 积分:1