这是我个人的写作，p80_7款PC

定时减法计数。输入数据0到9之间三位数，开始计时，每秒减一。当计数完成时，可做二次开发。还可做简单加减法-Timing counts subtraction. Input data between the three-digit 0-9, start running, by one per second. When the count is complete, do the secondary development. Also to do simple addition and subtraction

基于JAVA的3D坦克游戏源代码 -Java-based 3D tank game source code

4*4键盘扫描，依据键值，LCD双行显示，双行显示满后，清屏，重新显示-4* 4 keyboard scanning, based on keys, LCD double display, double line after the expiry of the Qing-ping, re-display

这是c++种比较实用的优先级的选择问题，主要为了资料的查阅方便-c++batter choice

此驱动程序不同网上流通的驱动,是具有时用性,可移值性相当高,是真正能使用的驱动子程序!程序中宏定义很清楚-this driver online circulation of different drive is used, can shift relatively high value property, really use the driver subroutine! Acer process definition is very clear

点阵显示 点阵显示-Dot-matrix display Dot Matrix display

4.4装配。。。嘟嘟程序，输入N个字符，N嘟嘟。（已完成）ysk3.asm。。。显示一个星形倒三角形。。。用asm编程把键盘输入的八个无符号二进制数转换成十六进制数和十进制数，并输出表单.asm... 使用子程序程序按以下三种格式（、TT、Short）打印九九成法标：（已完成）字符.asm... 小写字母a b c d。。。x y z ASCII分别为61H 62H 63H 64H 78H 79H。。。7AH和大写字母A B C D。。。。X Y Z ASCII分别为41H 42H 43H 44H 58H 59H L1.5AH…，使用字符串处理编程指令，从键盘上输入16个字符（字母和其他区分大小写的字母数字二者），记入BUF1启动存储区并将其传输

从键盘输入两个数字(0~7)之间 （1）用16进制表示两个数的和 （2）用四位二进制表示两个数的差，结果一定>=0 （3）用两位十进制表示两个数的积 exemple:-keyboard input from the two figures (0 to 7) between (a) a 16-band, said the number two and (2) with four two binary said the number of poor, the results would certainly gt; = 0 (3) with two decimal number two said the plot example :

在保存.5下编译ucos的案例，非常方便想了解ucos的入门者-In the preservation of the compiler under .5 uCOS case, a very convenient entry uCOS would like to know who

利用对网卡RTL8139的开发,使PC硬盘,网卡,口令为一体,从而实现对硬盘数据的保护.-use of the card RTL8139 development to make the PC hard drive, network card, passwords as one. thus the hard drive data protection.