Pipe类 Pipe类 Pipe类

基于B/S的人事工资管理系统采用ASP.net（c#）写的软件工程课设-Based on B/S in human resources management system uses ASP.net (c#) to write the software engineering course is located

linux-2.6内核下的usb驱程移植说明文档-linux- 2.6 kernel under the usb drive-transplant documentation

新编剑桥商务英语（BEC）（中、高级）词汇-New Business English (BEC) (senior) vocabulary

迷宫探险游戏是一个在turboC2环境下编写的小游戏，该游戏是根据DxBall撞球游戏进行设计的具有简单的撞球功能的游戏-maze is an adventure game in turboC2 environment prepared by the small games, the game is based DxBall balls for the design of the game is simple function of the pool games. .

一维支持向量机回归以及二维支持向量机回归-One-dimensional support vector machine regression, as well as two-dimensional support vector machine regression

cc1100代码，我也是从网上找的，拿来共享-cc1100 code, I am also looking for from the Internet, used to share

现在有好多初学jsp的网友经常会问数据库怎么连接啊，怎么老出错啊？所以我集中的在这写篇文章供大家参考，其实这种把数据库逻辑全部放在jsp里未必是好的做法，但是有利于初学者学习，所以我就这样做了，当大家学到一定程度的时候，可以考虑用MVC的模式开发。-now have many novice jsp netizens often ask how database linking ah, ah how old mistakes? So I concentrated on writing this article for reference. Such logic of the database on all jsp Lane is not necessarily a good one, but is conducive to beginners learning, So I do this, when we learn a certain extent, we can consider the use of the MVC pattern of development.

LabView中，将字符串以指定分隔符分解为数组-LabView, take assigns the character string the separation symbol to decompose as the array

1.为迴圈跑過任三點的組合的用三個2.为迴圈跑這三點以外的其他點的再用一個3.如果第四點與選定三點之任兩點所圍三角形面積合、 等於選定三點的面積、 代表第四點在三角形內ex： △abc = △abd + △acd + △bcd，d在△內4.如果符合條件、 把面積存起來、 用於之後比較面積大小5.面積大的取代面積小的6.印出面積最大三角形

单循环赛中选手胜负序列求解问题 名称：单循环赛中选手胜负序列求解问题 内容：有n个选手 P 1 ,P 2 ,P 3 ,… ,P n 参加了的单循环赛，每对选手之间非胜即负。现要求求出一个选手序列 P 1 ,P 2 ,P 3 ,… ,P n , 使其满足 P i 胜 P i+ 1 (i=1,… ,n-1) 。 -Single round robin tournament players winning sequence to solve the problem name: the outcome of single round-robin tournament players to solve the problem sequence elements: There are n-player P 1, P 2, P 3, ..., P n participated in a single round-robin between each pair of players Non-win or negative. Players are now required to find a sequence of P 1 " , P 2" , P 3 " , ..., P n" , to meet the P i " W P i+ 1" (i = 1, ..., n-1).