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STEVE的工具库
STEVE的工具库-STEVE library of tools
- 2022-05-25 12:22:07下载
- 积分:1
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morphology gray values and the values achieved two code
形态学灰值和二值的实现代码-morphology gray values and the values achieved two code
- 2023-06-17 02:10:04下载
- 积分:1
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C language Multiplier
用C语言实现的乘法器-C language Multiplier
- 2022-01-27 19:14:22下载
- 积分:1
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一个复数运算的例子
一个复数运算的例子-Example of a complex computing
- 2022-02-28 08:54:33下载
- 积分:1
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实施基本例程在Matlab和奥克塔夫(目前利用Matlab R13)为S.
implement basic routines in Matlab and Octave (currently using Matlab R13) for simulating adaptive beamforming and filtering for antenna arrays.
- 2023-02-01 14:30:03下载
- 积分:1
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ICEM CFD基础教程,学习流体力学的朋友可以参考。
ICEM CFD基础教程,学习流体力学的朋友可以参考。-ICEM CFD Basic Course, learning hydromechanics friends can refer to.
- 2022-12-07 20:30:04下载
- 积分:1
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n皇后问题的进阶解法,算法简单,注意输入的N可能没有解,比如2...
n皇后问题的进阶解法,算法简单,注意输入的N可能没有解,比如2-n Queen of the intermediate solution, the algorithm is simple, pay attention to the N input may not solved, such as the two
- 2022-07-08 20:45:07下载
- 积分:1
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功能:返回双精度参数的反全余弦的三角函数值 返回返回双精度参数y和x的数值由公式y/x计算的反正切三角函数值...
功能:返回双精度参数的反全余弦的三角函数值 返回返回双精度参数y和x的数值由公式y/x计算的反正切三角函数值-function : to return to double-precision parameters of the whole anti-cosine value of the trigonometric function to return to double-precision parameters x and y values from the formula y/x calculating the arc tangent trigonometry value
- 2022-02-07 09:17:04下载
- 积分:1
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performance simulation of network_coding
应用背景In generated networks, selecting one node as source and some nodes as receivers in
random (single source multicast network), we make performance test for network
coding based multicast route algorithm (we put forward it ourselves, corresponding to
high multicast rate and low multicast rate), shortest path distribution tree route
algorithm (DIJKSTRA algorithm) and Maximum-rate distribution tree route
algorithm (PRIM algorithm), respectively.
关键技术
In this program, two things have been done: (1) generate random topologies (2)performance test。
network coding cap: 5.0000 dijk cap: 5.0000 prim cap: 5.0000 network coding res1: 0.0000--res2: 12.0000 dijk res: 14.0000 prim res: 14.0000 average degree: 2.
- 2022-11-16 07:10:03下载
- 积分:1
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acm.zju.edu.cn第1234题(动态规划)
acm.zju.edu.cn第1234题(动态规划)-acm.zju.edu.cn that resolution 1234 (dynamic programming)
- 2022-07-12 17:46:54下载
- 积分:1