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This is a game that is to write a procedure to understand
这是有一个比赛题,是写出一个看不懂的程序-This is a game that is to write a procedure to understand
- 2022-07-18 10:17:37下载
- 积分:1
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Bezier曲线绘制,可以实现多种调解需求,交互能力很强。
Bezier曲线绘制,可以实现多种调解需求,交互能力很强。-Bezier curve drawing, you can realize a variety of mediation demand, the capacity of a strong interaction.
- 2022-03-11 20:51:54下载
- 积分:1
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VC开发GIS,用来显示地图比例尺,这在GIS开发过程中是常见的....
VC开发GIS,用来显示地图比例尺,这在GIS开发过程中是常见的.-VC GIS, is used to map scales, which in GIS development process is common.
- 2022-08-10 22:04:25下载
- 积分:1
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跟踪调试输出字符串
VC中追踪调试输出字符串-VC tracking debug output string
- 2022-05-21 23:26:57下载
- 积分:1
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算出access数据库密码,包括97和2000版本!
算出access数据库密码,包括97和2000版本!-Calculate the access database password, including the 97 and 2000 versions!
- 2022-02-20 12:49:31下载
- 积分:1
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Win32Asm教程
Win32Asm教程-Win32Asm Guide
- 2023-04-22 18:45:08下载
- 积分:1
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北大ACM试题poj 第3057题源码,很好的代码,希望对搞ACM的同学有帮助...
北大ACM试题poj 第3057题源码,很好的代码,希望对搞ACM的同学有帮助
-Peking University ACM Chapter 3057 question Question poj source code, good code, and want to help students engage in ACM
- 2022-08-24 17:04:45下载
- 积分:1
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这是一个Matlab程序计算PSD也绘制一个图来说明这些…
it is a program in matlab to calculate psd and it also plot a graph to show these
- 2023-03-20 17:50:03下载
- 积分:1
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海康威视央视
/ / ---------------------------------------------------------------------------#包括#语用hdrstop#包括“frm_config。”#包括“主。”#包括“error_msg。”/ / ---------------------------------------------------------------------------# pragma包(smart_init)#语用资源”。DFM”发生一事件* 1;/ / ---------------------------------------------------------------------------__fastcall发生一事件发生一事件::(tcomponent *的所有者)平台(业主):{}/ / ---------------------------------------------------------------------------国际__fastcall发生一事件::getdvrconfig(){int结果;net_dvr_devicecfg deivcecfg;的DWORD bytesreturn;而(真正的){如果(!net_dvr_getdvrconfig(Form2 -> user_id,net_dvr_get_devicecfg,1,和deivcecfg,sizeof(net_dvr_devicecfg),与bytesreturn)){被(错误(net_dvr_getlasterror()));结果= 1;打破;}dw_size ->标题deivcecfg.dwsize;dw_name ->标题=(char *)deivcecfg.sdvrname;
- 2022-08-18 18:53:23下载
- 积分:1
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能够找到逆序对。主要思想是通过先对一个数组进行归并排序,然后在加入求逆算法...
能够找到逆序对。主要思想是通过先对一个数组进行归并排序,然后在加入求逆算法-Able to find a reverse right. The main idea is to first merge sort an array, and then joining the inverse algorithm
- 2022-02-25 14:13:15下载
- 积分:1