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CodeLineCounter

于 2020-06-21 发布
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代码说明:

说明:  源代码统计工具可以统计C、C++、C#、Java等主流语言的源码行数(Source code statistics tools can count the number of source lines in mainstream languages such as C, C++, C#, Java, etc.)

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  • 很奇怪,这是一种数学方法,可以构造解。描述…
    这题奇数是有数学方法的,可以构造出解。描述起来比较麻烦。 出一解的构造法: 首先在整个矩阵的最下面一行的中央置1, 然后向右下方向顺序填上2,3,4,5,6,7,…… 注意碰到底的时候就将数翻到上面去,碰到右边的时候就翻到左面去 比如5*5的幻方,如果1填在(5,3)处,2就应该填在(1,4)处,4就应该填在(3,1)处…… 另外,当原数的下方已经有数时,要将要填入的数填到原数正上方 仍举5*5幻方的例子,当5已填好(4,2)时,其右下方为1,不能把6填在那里,而应填在(3,2)处,即5的上方。 最后,一个特殊的点,右下角,这时也应当将新数填在右下角的上方。-odd that this a mathematical method of solution can be constructed. Description relatively trouble. From a structural solution to the law : First, the entire matrix of the bottom of his home a central, then under the direction of the right order to fill 2,3,4,5,6,7 ... to the end of the encounter will be a few turns to above, where the right time to turn left on to For example, the 5* 5 magic squares, fill in if a (5,3), the two should fill in (1,4), four should be filled in (3,1) Department ... Also, when the original number at the bottom of several that should be filled to fill several the original number is still above 5 5* For Magic Squares example, when the five have completed (4,2), for its lower right
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    这是SYBASE的实验指导 里面有许多的代码 过程详细 欢迎各位多多下载 -This is the experimental guide contains many detailed process of the code to welcome you download lot
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