多线程

瑞萨官方提供的串口例程，见附件。运行起来的效果与官方说明的一样(For the serial routines provided by Risa, see the annex. It works just as well as the official instructions.)

匹配滤波器 波束形成和线性调频型号matlab程序(Matched filter beamforming)

说明：  MATLAB环境下利用YALMIP调用CPLEX12.90，UnitCommitment代码(Under the conventional two-stage dispatching framework, network-constrained unit commitment and economic dispatch are realized.)

说明：  找到C++大学教程第九版的电子书，服务于学生及C++初学者(Find out the PDF of the ninth edition of C + + university course for students and C + + beginners)

资源描述一个关于单片机led灯的实验，有Isis图和编程代码，刚入门的初级人士可以看看

Code to create a webaplication very basic on java

说明：  《Ｐｙｔｈｏｎ３反爬虫原理与绕过实战》随书源码，不错的资源哦("Python 3 anti crawler principle and bypass the actual combat" with the book source code, a good resource Oh)

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.

AD538的相关资料，对于实现线性化电路十分有帮助-AD538 relevant information, for the achievement of linear circuits very helpful

说明：  因子图优化最好的后端优化库之一，结构清晰，代码简洁易懂，很不错。(Factor map optimization is one of the best back-end optimization libraries, with clear structure, simple and easy to understand code, which is very good.)