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PDFManual
it is useless, i am sorry
- 2020-06-16 02:00:01下载
- 积分:1
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单纯性法C++
说明: 使用单纯形法求解线性规划问题,求最优解不停迭代(Simplex method is used to solve linear programming problems and the optimal solution is iterated continuously.)
- 2020-06-23 21:20:01下载
- 积分:1
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服务助手
说明: 一行一个,附带命令行,如果启动失败,在命令行前加一个空格(Line by line, with a command line. If startup fails, add a space before the command line.)
- 2019-02-18 01:46:03下载
- 积分:1
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可以用它来编辑各种各样的语言程序,大大减轻你的工作强度
可以用它来编辑各种各样的语言程序,大大减轻你的工作强度-Can use it to edit a variety of language program, greatly reduce the intensity of your work
- 2022-02-15 09:37:15下载
- 积分:1
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FAT32_SD-Interface-C-function
在SD卡上实现FAT32文件系统,C实现,可程序结构清晰,简单易懂。里面还有一篇介绍FAT32文件系统的文档,学习代码之前,请耐心将pdf文档研读一遍,这样能达到事半功倍的效果(mplemented on the SD card FAT32 file system, C realized, program structure clear, simple and understandable. There is also a description of the document FAT32 file system, learning code, please be patient to read pdf documents again, so to achieve a multiplier effect。)
- 2013-10-12 08:47:39下载
- 积分:1
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i2c 测试demo i2c-adapter
说明: i2c 测试demo,适用于i2c调试,可以适用示波器测量波形确认i2c是否通。(I2C test demo, suitable for I2C debugging, can be applied to oscilloscope measurement waveform to confirm whether I2C is passable.)
- 2020-06-25 05:20:02下载
- 积分:1
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案例1 BP神经网络的数据分类-语音特征信号分类
前馈循环神经网络,用于处理语音识别,里面是matlab源代码,以及实例。学习神经网络算法很有帮助。(Feed forward recurrent neural network for speech recognition, which is the matlab source code, and an example. Learning neural network algorithms is very helpful.)
- 2018-01-09 15:34:37下载
- 积分:1
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bragge
啁啾光纤光栅的Matlab程序,给出了相应的源程序,产生的refl记录了反射和透射谱。(Chirped fiber grating Matlab program, gives the corresponding source code, the resulting refl recorded reflection and transmission spectra.)
- 2009-12-29 09:59:05下载
- 积分:1
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OFDM with PAPR reduction
说明: 怎么样写好一篇文章很重要,不仅要会创新还要掌握一定的技巧,OFDM频分复用(How to write a good article is very important, not only to be able to innovate but also to master certain skills,OFDM frequency division multiplexing)
- 2020-11-13 21:35:05下载
- 积分:1
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人机对弈,互取火柴。取最后一根者输。每次至少取一根,最多取4跟。如果人先取则人必输。如果机先取,则机器等待人出错。否则人胜。...
人机对弈,互取火柴。取最后一根者输。每次至少取一根,最多取4跟。如果人先取则人必输。如果机先取,则机器等待人出错。否则人胜。-Human-computer game, and take matches. The last one loses. Check at least one of each, with up to 4 check. If the person is who will get lost. If the machine to check, then wait for others to machine error. Otherwise, people win.
- 2022-02-07 14:11:00下载
- 积分:1