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Josephus(data_struct)
数据结构中基于约瑟夫环问题,用C++方式实现的。。。。。(Data structure based on Josephus problem with C++ a manner. . . . .)
- 2013-11-17 11:30:24下载
- 积分:1
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Poly
多项式相加的数据结构试验·············(Polynomial sum test data structure)
- 2010-12-24 15:11:55下载
- 积分:1
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PrintTheSchedule_DataStructure_Lab4
数据结构试验-打印输出计算机本科专业4年每学期的课表;C++实现;图的邻接表存储结构以及拓扑排序的基本思想(Data structure test- printout computer 4 years of undergraduate per semester timetables C++ achieve basic idea of the adjacency table storage structure and topological sorting)
- 2012-11-24 23:30:41下载
- 积分:1
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huffman_tree
数据结构学习中提供的不错的源码,一个哈夫曼树类,利用了链队列存储结构。压缩包中有七个文件。(Data structure provided a good learning source, a Huffman tree class, the use of the chain queue storage structure. There are seven compressed file.)
- 2013-12-28 15:21:48下载
- 积分:1
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huffman_tree
数据结构学习中提供的不错的源码,一个哈夫曼树类,利用了链队列存储结构。压缩包中有七个文件。(Data structure provided a good learning source, a Huffman tree class, the use of the chain queue storage structure. There are seven compressed file.)
- 2013-12-28 15:21:48下载
- 积分:1
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ahuangCD
这个是数据结构课程设计中阿黄的CD的程序代码的工程文件包(This is a data structure curriculum design A yellow CD program code works package)
- 2013-12-21 18:53:00下载
- 积分:1
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sort.cpp
各种排序的模板实现,并分析了各种实现的时间复杂度及改进办法(Templates of various sort, and analyze the time complexity of the various implementations and ways to improve)
- 2012-04-14 03:08:18下载
- 积分:1
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9
说明: 任意给定输入的一个小写英文字符串a1a2a3…an-1an (n≥5)
输出:字符串Ana1An-1a2An-2a3…A2an-1A1an,其中Ai为ai的大写形式
例如,输入aybdx,则递归程序输出XaDyBbYdAx
(Any given input of a lowercase string a1a2a3 ... an-1an (n ≥ 5) Output: the string Ana1An-1a2An-2a3 A2an-1A1an, which Ai ai uppercase for example, input aybdx recursive program output XaDyBbYdAx)
- 2012-05-30 10:59:39下载
- 积分:1
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Lecture6
数据结构中链式队列和堆栈的循环用法,非常有用(Queue data structure in the chain and the cycle stack usage, very useful)
- 2011-07-27 15:30:29下载
- 积分:1
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astar
A*算法 1、将开始节点放入开放列表(开始节点的F和G值都视为0)
2、重复以下步骤:
在开放列表中查找具有最小F值的节点,并把查找到的节点作为当前节点
把当前节点从开放列表删除, 加入到封闭列表.
(A* algorithm 1, will begin to node placed in the and opening up list of (the began to node of the F and G values are regarded as 0) 2, repeat the the following steps: to Find a the has a the the smallest F value of the node in the the and opening up list of, and put Find a to the node as the current node current node is removed from the open list, added to the closed list.)
- 2013-04-04 11:06:42下载
- 积分:1