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VC_Matlabairconditon
VC_Matlab air conditon主要讲述了基于VC 和Matlab环境下的空调设计方案(VC_Matlab air conditon mainly about VC and Matlab environment based on air-conditioning design)
- 2010-09-17 17:07:31下载
- 积分:1
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C-Kalman
卡拉曼滤波器的c语言实现!非常好!很可以初学者使用!(Karaman filter c language! Very good!)
- 2011-10-21 15:59:29下载
- 积分:1
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TestApplications
test tapi applications
- 2014-11-29 23:49:37下载
- 积分:1
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matlib
matlib.h,matcom4.5的头文件(matlib.h, matcom4.5 header file)
- 2012-11-03 17:46:07下载
- 积分:1
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dandaofangzhen
c++ 通用弹道仿真计算程序(经典版)lalalalla(C dandaofangzhenchengxudfdfdfdfdf)
- 2013-09-08 13:55:54下载
- 积分:1
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matlab12
由于libsvm的matlab版本的工具箱libsvm-mat并没有给出寻参的函数模块,而无论利用libsvm工具箱进行分类还是回归,参数的选取是十分重要的,鉴于此libsvm-mat-2.89-3[FarutoUltimate3.0]在
libsvm-mat-2.89-3的基础上给出相应的辅助函数插件,方便用户来选取最佳的参数,现对该工具箱里主要的辅助函数插件的接口进行介绍。(As the matlab version of the toolbox libsvm libsvm-mat and did not give to find a function module parameters, regardless of classification using libsvm toolbox or regression, parameter selection is very important, in view of the libsvm-mat-2.89-3 [ FarutoUltimate3.0] in libsvm-mat-2.89-3 is given on the basis of the corresponding auxiliary function plugin user to select the best parameters, the toolbox is the main interface to plug the auxiliary functions are introduced.)
- 2011-05-23 16:28:40下载
- 积分:1
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trayicon
this is windows trayicon sample code.
- 2014-09-20 22:33:10下载
- 积分:1
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tiaojian
编码是在MATLAB下编写的,可以在MATLAB上直接运行,我没有在分类中找到MATLAB,所以选择了c++,希望管理员能分下类。这款编码是计算水准测量中计算条件平差的。(The code is written in MATLAB, you can run directly in MATLAB, MATLAB, I did not find in the classification so chose c++, I hope that the administrators in the next class. This code is calculated in the calculation leveling adjustment of condition equations.)
- 2012-05-29 09:14:21下载
- 积分:1
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11032112326d2526bf92eec85a
格兰杰因果关系检验 matlab和C的源代码,可以直接输入(Granger causality test matlab and C source code can be entered directly)
- 2020-10-24 11:07:21下载
- 积分:1
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2DMaxima
在二维空间里有两个点A=(X1,Y1)和B=(X2,Y2),如果X1>X2并且Y1>Y2 ,我们认为A优于B,A是这个集合的最大极值点,在给定的二维空间里的N个点的集合S中,找出最大极值点。(In two-dimensional space, there are two points = A = (X1, Y1) and B (X2, Y2), if the X1 and Y1 > X2 > Y2, we think that A is superior to B, A is the biggest extreme value point of the set, in A given set of N points in the two-dimensional space S, find out the most extreme value point.)
- 2013-12-24 21:02:56下载
- 积分:1