Kmeans

这是一道典型的动态规划题 提供了三种方法(用C++代码实现)-This a typical dynamic programming that provides three methods (using C code realization)

名片管理小系统实施源码-small business card management system is implemented FOSS

My realization of binary tree. This example is search tree.

上海交通大学数据结构课程的课后作业系列3.5：仅供参考，最好还是自己去写(Shanghai Jiaotong University data structure course homework Series 3.5: for reference, it is best to write their own)

这是关于古代9连环问题的求解过程，包括安装跟坼卸-This is a chain of nine ancient problem solving process, including the installation of crack with dumping

数据库连接，利用按钮一键即可，按钮特效也很是漂亮！-Database connection, using one button button, button effects are also very pretty!

广义表的反序 逆置广义表的递归模型如下： F(LS) = null 　　　　　　　　　　　　　若 LS 为空 F(LS) = LS 　　　　　　　　　　　　　若 LS 为原子，且 tail(LS) 为空 F(LS) = append( F(tail(LS)), head(LS) ) 　若 LS->tag=0 ，且 LS->tp!=null F(LS) = append( F(tail(LS), F(head(LS)) ) 　若 LS->tag=1 其中 append(a,b) 的功能是将广义表 a 和 b 作为元素的广义表连接起来。-Generalized table set against the broad anti-order recursive model of the table is as follows: F (LS) = null if the LS is empty F (LS) = LS if LS for the atoms, and the tail (LS) is empty F (LS) = append (F (tail (LS)), head (LS)) if the LS-> tag = 0, and the LS-> tp! = null F (LS) = append (F (tail (LS), F (head (LS))) If the LS-> tag = 1 where append (a, b) function is a generalized form, and b as elements of generalized tables connected.

堆栈程序！关于数据结构-stack procedures! On the data structure

labyrinth: you need to find the doable way to go to the destinaton.And then print out the path.-labyrinth: You need to find the doable way to go to the destinaton.And then print out the path.

输入迷宫行列数，1代表墙0代表路，之后系统生成路径(Enter the maze ranks number 1 represents 0 for Wall Road, after the system-generated path)