分析计算电网谐波，得出基波和高次谐波的值

A book that explains tool Ms Flex Grid in visual Basic 6

说明：  直接调用矩阵的函数库，方便矩阵的相关运算(Call the function library of matrix directly to facilitate the related operation of matrix)

简单的鼠标画线Vb源代码,有需要的就下载吧。(Simple mouse to draw lines Vb source code, there is a need to download it.)

设计一个名为Account类。这个类包含： （1）一个名为id的int型数据域，表示账户的身份号（默认值为0）。 （2）一个名为balance的double型数据域，表示账户余额（默认值为0）。 （3）一个名为annualInterestRate的double型数据域，保存当前年利率（默认值为0）。 （4）一个无实参构造函数，创建一个默认账户。 （5）id、balance和annualInterestRate的访问器和更改器函数。 （6）一个名为getMonthlyInterestRate（）的函数，返回月利率。 （7）一个名为withDraw的函数，从账户中支取指定金额。 （8）一个名为deposit的函数，向账户中存入指定金额。 画出类的UML图，实现类。编写一个测试程序，它创建一个Account对象，其ID为1122，账户余额为20000，年利率为4.5 。使用withDraw函数取出2500美元，使用deposit函数存入3000美元，然后输出账户余额、月利率和账户创建时间。(Design a class named Account. This class includes: (a) a named data type int id field that indicates the account identification number (default is 0). (2) a double-called balance of data fields, which means that the account balance (default is 0). (3) a double type named annualInterestRate of data fields, save the current interest rate (default is 0). (4) a no-argument constructor creates a default account. (5) id, balance and annualInterestRate access control and change control functions. (6) a named getMonthlyInterestRate () function returns a monthly rate. (7) a function named withDraw, drawn from the account specified amount. (8) a function called deposit to the account into a designated amount. Draw a UML class diagram, the implementation class. Write a test program that creates an Account object, its ID is 1122, the account balance is 20,000, an interest rate of 4.5 . Use withDraw function out $ 2,500, $ 3,000 deposit with deposit function, and then outputs the account balance, m)

software example for creating an app in mfc

Civilization Game Source Code in C++

MELPe fixed point 2400/1200bps

说明：  这是个小小游戏，小时侯我们特爱玩的那种魔方块，不知大家玩过否？有什么改进希望大家能发信息给我，(This a small game, turkey we catch a special kind of magic squares, I do not know whether you have played? What we can hope to improve the information to me, thank you)

输入一个矩阵，可以求得该矩阵的逆矩阵，内附解释说明(Enter a matrix, you can obtain the inverse matrix, containing an explanation)

freescale .S19目标文件，走CAN线通信的bootloader上位机，要么不上传，上传的都是经典(freescale bootloader Client)