网格布局css画廊

24点游戏脱胎于作者8年前设计的24点游戏DOS版,现新版本具有以下特色: > 1.允许自动抽牌或手动抽牌,答案结束电脑将尽可能给出该题所有的解答. > 2.允许通过多种方法改变游戏的界面:一是预置了7种换肤方案,二是游戏者可自行规定窗口的颜色 > 3.独创的电脑智能自学习功能，可吸收用户的算法扩充系统的“棋谱”(内置算法59*24=1416条). > 4.内置13个彩蛋，包含了许多有待你发现并激活的隐藏功能（如函数计算器、界面换肤、婚纱图片、控制计时、3D动画、鼠标右键、“作弊”设置等功能），大大增添游戏的趣味性！ > 5.游戏过程真人原声支持 > 6.支持乘方，支持不同的计时方案，支持游戏目标值（如24）与选牌在１００以内自然数的自定义。 > 7.提供键盘或鼠标输入的智能模糊支持功能（如全角与半角纠正，括号纠正、运算符号输入自动纠错）,提供了功能键支持 > 8.独特的计分方案，用时越少，加分越高！ > 9.支持不同时间级别的分级纪录功能 > 10.数据文件防病毒自动校验修复功能。经改进，现只需一个不到300K的主程序文件即可有声有色地运行本游戏（暂不支持网络对擂）。 > 福建师范大学化学与材料学院 曹阳-24 point game modeled on the author eight years ago designed 24 points DOS version of the game, is the new version has the following characteristics : gt; 1. Pumping licensing allows automatic or manual pumping license, the answer will be the end of the computer is possible that all the answers. Gt; 2. Through a variety of methods to allow change the game changed the interface : One is included in the seven Eurocargo programs, two games will be to dec

CDImage的接口

计算语音信号的信噪比和分段信噪比，在matlab中使用(Computing signal-to-noise ratio and segmentation SNR of speech signals are used in MATLAB)

python语言实现多项式秘密分享，并且可以用拉格朗日插值恢复(Python language implements polynomial secret sharing and can be restored by Lagrange interpolation)

matlab image to avi视频-matlab image to avi video

Project : Simple AVR Clock

说明：  皮秒脉冲泵浦产生超连续谱程序，有无拉曼，自适应步长，四阶龙格库塔(Supercontinuum program produced by picosecond pulse pump)

液晶驱动程序 驱动芯片为t6963 包含文字字模 及图片-LCD Driver IC for t6963 contain text and photographs Fonts

在linux开发环境下采集Hokuyo雷达输出数据的程序(sampling Hokuyo output data program)

1.NEH principle (1) the processing time of each workpiece on all machines is summed; the summed values are sorted from large to small; (2) first select the first workpiece (the longest processing time), with the second workpiece into the first workpiece before and after the two positions, calculate makespan, small is saved; (3) fix the sequence in the previous step, insert the next workpiece into the previous workpiece, and compare the smallest makespan and save it; (4) Repeat the previous step to arrive at the final result.