人员疏散 障碍物 元胞自动机原理testend

说明：  ATAN VHDL iplementation

说明：  matlab仿真代码，适合初学者学习，包括产生GFDM信号并于OFDM进行PAPR比较(Matlab simulation code, suitable for beginners to learn.)

帮助新手熟悉用C语言开发小型系统-help newcomers familiar with the C language development of small systems

CDMA系统中的有关多用户检测的MATLAB仿真程序和Simulink仿真模型-CDMA systems on multi-user detection of MATLAB and Simulink simulation model simulation program

经典问题：母牛问题，只是一个作业，希望能对初学者有点帮助(Classic problem: cow problem, is just a job, hoping to be helpful for beginners)

液晶1602显示程序 基于飞思卡尔单片机(LCD display program based on Freescale' s MCU 1602)

本文介绍了一种新型变刚度执行机构(CompAct-VSA)的设计与建模。压实- vsa的工作原理是基于具有连续调节枢轴点的杠杆臂机构。提出的概念允许开发具有大刚度范围和快速刚度调节响应的驱动单元。执行机构的实现利用凸轮形杠杆臂与可变枢轴驱动齿条和小齿轮传动系统。这种实现导致了高度集成和模块化的组装。尺寸和重量确实是VSAs设计中的一个开放问题，这最终限制了它们在多自由度机器人系统中的实现。本文介绍了执行机构的原理、工作原理和模型。初步结果表明，所提出的压实vsa设计具有快速的刚度调节响应和较大的刚度范围。(This paper describes the design and modelling of a new variable stiffness actuator (CompAct-VSA). The principle of operation of CompAct-VSA is based on a lever arm mechanism with a continuously regulated pivot point. The proposed concept allows for the development of an actuation unit with a wide range of stiffness and a fast stiffness regulation response. The implementation of the actuator makes use of a cam shaped lever arm with a variable pivot axis actuated by a rack and pinion transmission system. This realization results in a highly integrated and modular assembly. Size and weight are indeed an open issue in the VSAs design, which ultimately limit their implementation in multi-dof robotic systems. The paper introduces the mechanics, the principle of operation and the model of the actuator. Preliminary results are presented to demonstrate the fast stiffness regulation response and the wide range of stiffness achieved by the proposed CompActVSA design.)

用于解决9*9的数独，功能不完善,只能给出所有结果中的一种。(to solve Sudoku 9* 9 , function is not perfect.)

利用vc++开发的TIN的生成算法 (Using vc++ TIN generation algorithm developed)

编写一个函数，要求输入年月日时分秒， 输出该年月日时分秒的下一秒。 如输入2011年12月31日23时59分59秒， 则输出2012年1月1日0时0分0秒。 需要考虑闰年 和 2月的特殊情况 (Write a function that requires input date, hour, minute and second outputs of the date when the next second. If the input at 23:59:59 on December 31st, 2011, output at 0:00:00 on January 1, 2012. Leap year and February need to consider the special case)