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新编Marc有限元实例教程
编程教程,帮助入门学者学习建模,从初级开始,逐步深化,非常有帮助(Programming tutorials, help beginners learn modeling, from the beginning, gradually deepen, very helpful)
- 2019-01-14 19:19:06下载
- 积分:1
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IEEE4-5-14-30-57-118-300
潮流计算,IEEE30节点的潮流计算,和牛顿法的程序报告
(power flow)
- 2012-09-26 15:11:01下载
- 积分:1
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BeamFreqMode
细梁的振动,无量纲振动控制方程关于梁的动力响应(Beam power with applications from mechanical aerospace electrical and civil engineering free vibration nondimendional frequency coefficients on the dynamic behaviour of the beam)
- 2012-11-01 16:33:58下载
- 积分:1
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shdom
fortran语言的球谐函数离散坐标法大气传输模型主程序,可用于大气场景生成(FORTRAN, spheric harmonic function of the discrete coordinate method main program, the atmospheric transmission model can be used for the atmospheric scene is generated)
- 2020-10-11 09:57:33下载
- 积分:1
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norton-power-law
牛顿幂率蠕变法则的一个子程序-是一个经典的、常用的蠕变法则,在众多领域广泛使用(Newtonian power law creep rate of a subroutine- is a classic, conventional creep law, are widely used in many fields)
- 2021-04-01 20:49:08下载
- 积分:1
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a.c
Finding special triples of the form (n, n + 1, n + 2)
Write a program that finds all triples of consecutive positive three-digit integers each of which is
the sum of two squares, that is, all triples of the form (n, n + 1, n + 2) such that:
• n, n+1 and n+2 are integers at least equal to 100 and at most equal to 999
• eachofn,n+1andn+2isoftheforma2+b2.(Finding special triples of the form (n, n+ 1, n+ 2)
Write a program that finds all triples of consecutive positive three-digit integers each of which is
the sum of two squares, that is, all triples of the form (n, n+ 1, n+ 2) such that:
• n, n+1 and n+2 are integers at least equal to 100 and at most equal to 999
• eachofn,n+1andn+2isoftheforma2+b2.)
- 2012-04-26 15:05:05下载
- 积分:1
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Untitled
由Music算法估计线阵波达方向,搜索频谱波峰。(Estimation of linear array DOA by Music algorithm, searching spectral peak.)
- 2013-10-25 14:37:33下载
- 积分:1
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ykb
用雅可比方法求矩阵的特征值和特征向量的FORTRAN程序(Method using Jacobian matrix of eigenvalues and eigenvectors of the FORTRAN program)
- 2007-12-25 10:36:27下载
- 积分:1
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OpenSees1.0
经典的可编程添加模块的面向对象的有限元程序代码(C++ code for OOFEM based on multi-systems)
- 2018-05-02 19:45:18下载
- 积分:1
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program
FFT A计权 倍频程分析 三分之一倍频程分析(F F T A w eight o c tave a n al o n e t hird o ctave)
- 2011-12-07 14:02:04下载
- 积分:1