Lists

数据结构习题答案，线性链表的实现与适用，数据结构：思想与实现2-9(Data structure exercises answer, linear linked list implementations with applicable data structure: Ideas and Implementation 2-9)

根据队列搜索算法的基本思想，现设计了一个简单的结构体数组如下定义代码所示。此结构体数组具备控制结点搜索和存储结点信息和路径的功能，可以较好的实现TDN的最小时间路径搜索。(Search algorithm based on the basic idea of ​ ​ the queue is now designed a simple structure array as defined code. This structure array with the control node and storage node information search and path functions, you can achieve better TDN minimum time path search.)

说明：  从最后一个非叶子结点开始从后往前进行调整，保证了根下的所有子树都是最大堆，最后对根进行调整，使整棵二叉树为最大堆，保证了根结点为整棵数的最大值点，完成了建堆的过程，再将根结点跟最后一个结点进行交换，如此反复操作，则堆排序就完成了，其中堆排序的过程采用了满二叉树的概念。(From the final of a non-leaf node after the move began to be adjusted to ensure that the root of all sub-tree are the biggest pile, and finally adjusted to the root, so that the largest heap binary tree整棵to ensure that the root node for整棵the maximum number of points, completed the process of building reactors, and then the last root node with a node to be exchanged, and so repeated the operation, then HEAPSORT completed, of which the process of HEAPSORT a full binary tree concept.)

多项式加减乘 用数据节够得算法实现多项式的加减乘 原理简单易懂(suoxiangshi jiajiancheng)

给定一个带权的无向连通图,如何选取一棵生成树,使树上所有边上权的总和为最小(Given a weighted undirected connected graph, how to select a spanning tree to minimize the sum of all the upper bounds on the tree)

说明：  读取股票数据文件,C++源程序，非常好用。是学生做毕业设计的源料(Read the Stock Data File)

8_queen问题的一个自创的算法，还不错！(8_queen)

说明：  拓扑排序 　 对一个 有向无环图 G进行拓扑排序，是将G中所有顶点排成一个线性序列，使得图中任 意一对顶点u和v，若u，v ∈E，则u在线性序列中出现在v之前。 　 通常，这样的线性序列称为满足拓扑次序的序列，简称 拓扑序列 。 注意： 　 ①若将图中顶点按拓扑次序排成一行，则图中所有的有向边均是从左指向右的。 　 ②若图中存在有向环，则不可能使顶点满足拓扑次序。 　 ③一个DAG的拓扑序列通常表示某种方案切实可行。 (Topological sort In a directed acyclic graph G topological sort, is all vertices will G formed a linear sequence, make diagram post Meaning a pair of vertex u and v, if u, v ∈ E, then u in linear sequence in which they appear in v before. Usually, such linear sequence sequence of topological order called meet, abbreviation topology sequence. Note: (1) if the diagram according to the topology order line vertices, then figure all from left to right edge are pointing. (2) if the figure to exist in the ring, is impossible to have the vertex meet topological sequence. (3) a DAG topological sequence usually expressed some scheme is feasible. )

数字根算法，用最简单的代码计算数字根。如果把一个大数的各位数字相加得到一个和，再把这个和的各位数字相加又得一个和，再继续作数字和，直到最后的数字和是个位数为止，这最后的数称为最初那个数的“数字根”。(Digital root algorithm, with the most simple code to calculate the digital root. If you figure in a large numbers is the sum of a, then this and you figure the sum is again a, and then continue for digital and until the final figure and the single digits, the last number called initially that the number of "digital root".)

链表L，创建公有成员函数Split（A,B ），创建2个新表A,B，使的A 中含有L中奇数位置元数，B中含L偶数位置元数 (Chain L, create public member function Split (A, B), to create two new tables A, B, A so containing L odd position of a few yuan, B-L even a few locations yuan)