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22KB

于 2020-07-30 发布 文件大小:6413KB
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下载积分: 1 下载次数: 75
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代码说明：

  Ghost最新远程控制源码动态传输小马22KB 源码只供参考请勿用于非法用途！ (Ghost remote control source dynamic transmission pony 22KB)

文件列表：

DT
..\Bin
..\...\SkinH.dll,86528,2009-09-15
..\...\Update
..\...\......\Gh0stServer.exe,24576,2010-09-13
..\...\......\Open3389.dll,215552,2010-08-09
..\...\......\Plguins.dll,101376,2010-09-13
..\...\......\Server.Dat,13312,2010-09-13
..\...\......\Server.dll,11264,2010-09-13
..\...\Winds.exe,2011136,2010-09-13
..\...\Winds.ini,202,2010-09-13
..\common
..\......\Audio.cpp,5195,2008-03-27
..\......\Audio.h,1280,2008-03-19
..\......\CursorInfo.h,1810,2008-03-25
..\......\macros.h,4853,2010-09-13
..\......\VideoCodec.h,3636,2008-03-26
..\......\zlib
..\......\....\zconf.h,7810,2008-01-04
..\......\....\zlib.h,40900,2008-01-04
..\......\....\zlib.lib,81534,2007-11-14
..\gh0st
..\.....\AudioDlg.cpp,3600,2010-07-22
..\.....\AudioDlg.h,1652,2008-03-19
..\.....\BmpToAvi.cpp,1595,2008-03-26
..\.....\BmpToAvi.h,796,2008-03-26
..\.....\BuildServer.cpp,21503,2010-09-06
..\.....\BuildServer.h,2305,2010-09-01
..\.....\ChangeGroup.cpp,2516,2010-07-23
..\.....\ChangeGroup.h,1318,2010-07-23
..\.....\encode.h,1069,2008-01-18
..\.....\FileManagerDlg.cpp,72710,2010-07-22
..\.....\FileManagerDlg.h,6190,2010-07-22
..\.....\FileTransferModeDlg.cpp,1757,2007-12-28
..\.....\FileTransferModeDlg.h,1392,2007-12-01
..\.....\gh0st.clw,14444,2010-09-13
..\.....\gh0st.cpp,7258,2010-06-19
..\.....\gh0st.dsp,8120,2010-09-13
..\.....\gh0st.h,1523,2008-04-14
..\.....\gh0st.plg,1934,2010-09-13
..\.....\gh0st.rc,30327,2010-09-13
..\.....\gh0stDoc.cpp,1798,2010-07-22
..\.....\gh0stDoc.h,1432,2010-07-22
..\.....\gh0stView.cpp,6865,2010-08-30
..\.....\gh0stView.h,2139,2010-07-23
..\.....\include
..\.....\.......\Buffer.cpp,11677,2001-08-22
..\.....\.......\Buffer.h,1119,2008-01-25
..\.....\.......\CpuUsage.cpp,1467,2001-04-23
..\.....\.......\CpuUsage.h,1278,2001-04-23
..\.....\.......\IOCPServer.cpp,36498,2010-09-01
..\.....\.......\IOCPServer.h,5068,2010-09-01
..\.....\.......\Mapper.h,548,2001-08-22
..\.....\IniFile.cpp,2242,2008-02-16
..\.....\IniFile.h,1146,2008-02-16
..\.....\InputDlg.cpp,7080,2010-07-22
..\.....\InputDlg.h,2826,2008-03-24
..\.....\KeyBoardDlg.cpp,6056,2010-07-22
..\.....\KeyBoardDlg.h,1767,2008-04-18
..\.....\LogView.cpp,7367,2010-07-25
..\.....\LogView.h,1761,2010-07-21
..\.....\MainFrm.cpp,16951,2010-09-13
..\.....\MainFrm.h,2524,2010-07-23
..\.....\MoreChoose.cpp,6893,2010-09-06
..\.....\MoreChoose.h,1741,2010-07-23
..\.....\PcView.cpp,38019,2010-09-13
..\.....\PcView.h,3623,2010-09-13
..\.....\ReadMe.txt,1274,2008-02-24
..\.....\Release
..\.....\.......\gh0st.map,1697476,2010-07-22
..\.....\.......\Winds.map,1897608,2010-09-13
..\.....\removejunk.bat,398,2006-06-27
..\.....\res
..\.....\...\1.cur,326,2007-11-02
..\.....\...\2.cur,326,2007-11-02
..\.....\...\3.cur,326,2007-11-02
..\.....\...\4.cur,326,2007-11-02
..\.....\...\aero.she,30738,2010-05-16




..\.....\...\dot.cur,326,2008-02-06

..\.....\...\EventError.ico,4406,2010-07-23
..\.....\...\gh0st.ico,766,2007-11-01
..\.....\...\gh0st.rc2,397,2007-11-01
..\.....\...\keyboard.ico,766,2008-01-17
..\.....\...\shipin.ico,1406,2010-09-13
..\.....\...\system.ico,766,2008-01-16
..\.....\...\toolbar1.bmp,1846,2007-11-10
..\.....\...\toolbar2.bmp,1846,2007-11-10
..\.....\...\user.ico,894,2010-09-13
..\.....\...\webcam.ico,24190,2007-12-03
..\.....\...\无视频.ico,4406,2010-06-07
..\.....\...\有视频.ico,4406,2010-06-07
..\.....\resource.h,11894,2010-09-13
..\.....\ScreenSpyDlg.cpp,28807,2010-07-23
..\.....\ScreenSpyDlg.h,2788,2008-04-18
..\.....\SendPlugins.cpp,3101,2010-07-22

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  • Desktop
    调度问题的回溯算法，算法中的经典问题。问题描述：假设有n个任务由k个可并行工作的机器完成。完成任务i需要的时间为ti。试设计一个算法找出完成这n个任务的最佳调度，使得完成全部任务的时间最早。(Scheduling problem backtracking algorithm is the classic problem. Problem Description: Suppose there are n-task by the k-parallel machine can be completed. The time required to complete the task i is ti. Try to design an algorithm to find completing these n-best task scheduling, making the earliest time to complete all tasks.)
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  • jiaobingbu
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    2008-09-20 08:36:30下载
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  • medo
    设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。  编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits.  programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)
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  • vgpicker
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    2013-07-28 08:24:04下载
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    2021-04-07 14:59:01下载
    积分：1
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