daibaishai

GHOST 2012 原版远控 免杀好做的呢 大家来下吧(GHOST 2012)

rfid实例阅读程序，可实现超高频，高频，低频卡的读写( rfid实例阅读程序，可实现超高频，高频，低频卡的读写 RFID instance reading program, you can achieve ultra high frequency, high frequency, low frequency card read and write)

远程遥控家电，用到了串口程序源码，键盘程序源码，LCD显示出来来程序源码等等，非常不错的程序源码。比较有参考价值。 可直接使用。 (Remote control home appliances, used in a serial program source code, keyboard program source code, LCD display out to the program source, etc., very good program source code. Reference value. Can be used directly.)

设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。  编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits.  programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)

上万元的远控源码上万元的远控源码,超级给力，黑客必备！！(Million yuan of remote control remote control source code, super awesome, hackers must!! )

一个很好的远控，很强大，啊啊啊啊啊啊啊啊(A good remote control)

hangle unicode used AI

动态传输远程控制，已经发出了自己的，大家拿去玩吧(The dynamic transmission Remote Control has been issued, we take it to play)

gh0st1.0远程控制源码，VC++6.0编译通过。仅供大家学习参考！(h0st1.0 remote control source, VC++6.0 compile. We only learn reference!)

又一个类似PCAnywhere的远程控制软件源码，分客户端和服务器端。( A similar PCAnywhere long-distance control software source code, is divided the customer end and the server end. )