登录
首页 » matlab » MomentsHu

MomentsHu

于 2013-05-27 发布 文件大小:1KB
0 253
下载积分: 1 下载次数: 2

代码说明:

  Moment s Hu algorithm

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • matlab
    汽车仿真关于汽车经济性的源代码,很不错的资料。(car )
    2010-07-12 12:24:47下载
    积分:1
  • calib.0.0.1
    Vision multi-caméra pour la détection d obstacles sur un robot de service
    2014-12-02 22:23:58下载
    积分:1
  • Retinexenhancement
    这是一个非常好的视网膜皮层理论算法,里面含有代码。(This is a very good theoretical algorithm retinal cortex, which contains the code.)
    2009-12-11 21:38:06下载
    积分:1
  • matlab
    Matlab基本电路运算,只需要输入电路的基本信息如节点数,电源的电压。电流等即可得出电路所有的电量(Matlab basic circuit operation, and only need basic information such as the number of nodes of the input circuit, the power supply voltage. Current, etc. can draw all the power of the circuit)
    2012-05-21 20:05:47下载
    积分:1
  • zhuchengfen
    主成分分析法的一个例子程序,在建模中应用(Principal component analysis, an example program in the modeling application)
    2012-06-22 11:45:58下载
    积分:1
  • Fastdiscretecurvelettransforms
    This paper describes two digital implementations of a new mathematical transform, namely, the second generation curvelet transform [12, 10] in two and three dimensions. The first digital transformation is based on unequally-spaced fast Fourier transforms (USFFT) while the second is based on the wrapping of specially selected Fourier samples. The two implementations essentially differ by the choice of spatial grid used to translate curvelets at each scale and angle. Both digitaltransformations return a table of digital curvelet coefficients indexed by a scale parameter, anorientation parameter, and a spatial location parameter. And both implementations are fast in the sense that they run in O(n2 log n) flops for n by n Cartesian arrays in addition, they are also invertible, with rapid inversion algorithms of about the same complexity.
    2011-10-30 15:57:56下载
    积分:1
  • shannon
    香农编码,给定概率求码字,编码效率,平均码长(Shannon coding, the probability of seeking a given codeword, the coding efficiency, the average yards)
    2010-06-26 15:32:53下载
    积分:1
  • a
    说明:  用级数PI/4 = 1 -1/3 + 1/5 -1/7+…求PI的近似值,要求取前1000项来计算。(With a series PI/4 = 1-1/3+ 1/5-1/7+ ... seeking an approximation of PI, demanded before the 1000 data.)
    2010-04-14 13:19:56下载
    积分:1
  • A-1
    Programm is counting inverse matrix
    2011-06-10 22:08:22下载
    积分:1
  • Untitled2
    完成双目标定,利用标定参数校准源图像和目标图像,并计算得到其视差图(The binocular calibration is completed and the calibration parameters are used to calibrate the source image and the target image, and the parallax diagram is calculated.)
    2021-05-13 12:30:02下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载