Transfer_PDU_on_PUSCH

说明：  《ofdm关键技术与应用》（汪裕民）一书中第10章有详细说明，在MATLAB上跑过，没有问题(&quot Ofdm technology and application&quot (Wang Yumin) Chapter 10 of the book are detailed in MATLAB, Running, no problem)

希尔伯特-黄变换的代码，适用于分析非平稳信号(Hilbert-Huang Transform code applicable to the analysis of non-stationary signals)

LMS自适应均衡器算法，里面有比较详细的解释说明，适合初学者参考。(LMS adaptive equalizer algorithm, which has more detailed explanations, suitable for beginners reference.)

2,1,7卷积吗 ，实现vitebi译码(2.1.7Convolutional Codes and Viterbi decoding)

C 程序 球面方位角算法： azimuth.cpp CRC校验快速算法： CRC_Table.cpp 解扰码算法： scrambler.cpp Matlab 程序 信号带宽测量： BandWith.m 带通信号下变频： fqmv.m QPSK 解调 demodQpsk.m pwelch求功率谱的算法 psdwh.m 均值滤波算法 cvmn.m 信号正交分解： Cnv2Bas.m(C procedures spherical azimuth algorithm: azimuth.cppCRC Fast Algorithm checksum: CRC_Table.cpp Descrambling code algorithm: scrambler.cpp Matlab signal bandwidth measurement procedures: BandWith.m bandpass signal down-conversion: fqmv.mQPSK demodulator for demodQpsk.mpwelch power spectrum algorithm psdwh.m mean signal filtering algorithm cvmn.m orthogonal decomposition: Cnv2Bas.m)

归一化的函数，神经网络的必须。希望对大家有用。。。。(Normalized function, neural networks have. Hope to be useful. . . .)

Client objects implement io operations and cache pages.

ofdm系统仿真 含16qam调制 fft 加窗 加cp等模块 北京邮电大学通信系课设题目(ofdm system simulation)

利用随机几何方法和对基站协作场景下能量效率和协作基站数目的关系进行仿真(The stochastic geometry method is used to simulate the relationship between the energy efficiency and the number of cooperative base stations in the base station collaboration scenario)

OFDM系统通过在时域符号前插入大于信道冲击响应长度的循环前缀（CP）可以避免符号间干扰(ISI)和载波间干扰(ICI)。但是，过长CP会使得数据传输效率降低。可以采用最小均方误差（MMSE）信道缩短均衡技术来压缩信道冲击响应长度。(OFDM systems avoid inter-symbol interference (ISI) and inter-carrier interference (ICI) by inserting a cyclic prefix (CP) larger than the channel impulse response length before the time-domain symbol. However, long CP will reduce the efficiency of data transmission. A minimum mean square error (MMSE) channel shortening equalization technique may be employed to compress the channel impulse response length.)