0829-Binary-Tree

说明：  数据结构：Huffman编码。哈夫曼编码是哈夫曼树的一个应用。哈夫曼编码应用广泛，如JPEG中就应用了哈夫曼编码。 哈夫曼树又称最优二叉树，是一种带权路径长度最短的二叉树。(Data structure: Huffman coding. Huffman coding is an application of the Huffman tree. Huffman coding is widely used, such as JPEG in the application of the Huffman coding. Huffman tree, also known as the best binary tree is a weighted shortest path length binary tree.)

最优二叉搜索树问题具有最优子结构性质，即其任意一棵子树都是一棵独立的最优二叉搜索树，所以可以采用动态规划方法，并且在每次更新时保存子树的根。(Optimal binary search tree problem has optimal substructure property that any of its sub-tree are an independent optimal binary search tree, so you can use dynamic programming methods, and save each update subtree roots.)

mfc 连接数据库 用mfc做的管理系统，戏中包括数据库连接(mfc connect to the database)

希尔排序，希尔排序，希尔排序，希尔排序，c语言(shell sort)

求二叉树的深度: 给定一个有根二叉树，规定连接两个节点的每条边长度是1，定义树的深度为根到叶子节点距离的最大值。 (Description 给定一个有根二叉树，规定连接两个节点的每条边长度是1，定义树的深度为根到叶子节点距离的最大值。 )

数据结构快速排序例程代码，只要按照例子就可以很容易加入到你的程序当中。(Data Structures quick sort routine code, just follow the example you can easily add them into your program.)

说明：  线性表的基本运算及多项式的算术运算在顺序表泪SeqList 中增加成员函数void Reverse()实现顺序表的逆置 (Linear form the basic arithmetic operations and the polynomial form in order to increase tear SeqList member function void Reverse () to achieve the inverse order of the table set)

参加数学建模的同学很可能会遇到这套题。本程序采用链表进行编写，很方便地解决了小白鼠问题。(Mathematical modeling of the students participating are likely to encounter this question, the program uses the list to solve the problem of mice, very convenient.)

本程序实现一元多项式合并。本程序输入方式为按项输入，每输入一个项，会先提示输入项的幂，再提示输入项的系数。(This procedure combined to achieve a dollar polynomial. This procedure according to entry input methods for the input, one for each input item, it will first prompt entry of the power, and then prompts entry of the coefficient.)

最优二叉搜索树问题具有最优子结构性质，即其任意一棵子树都是一棵独立的最优二叉搜索树，所以可以采用动态规划方法，并且在每次更新时保存子树的根。(Optimal binary search tree problem has optimal substructure property that any of its sub-tree are an independent optimal binary search tree, so you can use dynamic programming methods, and save each update subtree roots.)