-
Newton_Bisection
数值计算中的二分法和牛顿迭代法的演示,通过对数值的计算(Numerical calculation of the dichotomy and the Newton iteration of the demonstration, through numerical calculation)
- 2009-03-14 09:43:52下载
- 积分:1
-
factor
此MATLAB程序实现函数的阶乘功能,经调试,完全正确(Procedures for implementation of this MATLAB function factorial function, with debug, completely correct)
- 2009-03-19 22:31:18下载
- 积分:1
-
junheng
在移动数据通信系统信号经传播媒介到达接收端会发生畸变,现行的通信系统普遍采用
自适应均衡技术来克服ISI和多普勒扩展。自适应均衡技术需要重复发送已知的训练序列直至
有效均衡为止I。“盲均衡(Blind Equalization,BE)111”技术仅利用接收序列本身的相关性便可
均衡信道特性。(Signal in the mobile data communication systems to reach the receiver via the mass media distortion occurs, the existing communication systems are generally adaptive equalization to overcome ISI and Doppler spread. Adaptive equalization techniques need to send a known training sequence repeated until an effective balance date I. " Blind equalization (Blind Equalization, BE) 111" technology is only used to receive serial correlation in itself can be balanced channel characteristics.)
- 2010-08-31 10:13:30下载
- 积分:1
-
lms
LMS滤波算法的matlab实现,有注释(LMS filtering algorithm)
- 2010-12-13 21:11:18下载
- 积分:1
-
2006311143731317
说明: 的支持是我前进的动力!
欢迎你来灌水!
如果想和我交换链接,请在留言区留言!
本blog资料的解压密码为sagestar!(support is the driving force for me! You are welcome to irrigation! If I want to exchange links, the voice-mail! This blog information extracting passwords sagestar!)
- 2006-04-06 18:27:00下载
- 积分:1
-
MIMO_OFDMbasedonLS
说明: MIMO-OFDM基于LS方法的几种滤波方法的比较(MIMO-OFDM-based LS method of comparison of several filter)
- 2010-04-20 09:50:10下载
- 积分:1
-
OFDM
文件中含有ofdm仿真的全过程,包4qam,8qam形式进行调制、解调,转换等过程(Ofdm simulation file contains the entire process, including 4qam, 8qam form of modulation, demodulation, conversion process)
- 2011-06-11 21:14:53下载
- 积分:1
-
Lab2
The Phantom of instantaneous
- 2013-09-23 17:00:26下载
- 积分:1
-
MSo_wave.tar
Multiple Source EM Wave propagation modeling via Finite Differences
- 2013-11-14 19:37:55下载
- 积分:1
-
DFC
Decorrelated fast cipher source code from state technical university in Russia
- 2014-01-13 15:08:23下载
- 积分:1