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calc_lz_complexity

于 2015-03-12 发布 文件大小:6KB
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  calculate limpel-ziv complexity of an image

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  • speech20040601
    说的是一个关于MATLAB使用的简单介绍的文件,对初学着还是有一顶帮助的(That is a study on the use MATLAB a brief document, on a beginner or a help)
    2008-06-12 21:05:50下载
    积分:1
  • a
    说明:  codes for matlab . .
    2011-02-22 13:27:56下载
    积分:1
  • fangjia
    房价的模拟与现实对比,得根据具体数据来对程序进行适当的调整,希望有用(Compare simulated and real house prices, by the specific data to make an appropriate adjustment to the program, seek to help)
    2011-06-20 09:27:56下载
    积分:1
  • 9fa8bb0ca0a5cfefbbc0354b5ace7b56
    2011 Dongcheng Teachers comptition
    2013-12-04 17:05:46下载
    积分:1
  • xil
    MATLAB源码,P0201:MATLAB赋值 P0202:MATLAB中的for循环 P0203:MATLAB中的for循环和if条件 P0205:MATLAB图像处理的基本操作 P0206:MATLAB高级图像处理操作 P0207:根据RGB图像创建一幅灰度图像 P0208:二值图像的取反操作 P0209:用imshow函数显示图像 P0210:在同一个窗口内显示两幅图像(MATLAB source code, P0201 : MATLAB assignment P0202 : MATLAB for the cycle P0203 : MATLAB for the cycle, and if conditions P0205 : MATLAB image processing basic operation P0206 : High MATLAB image processing P0207 : According to RGB images to create a gray-scale image P0208 : binary images from the operation of the anti-P0209 : use imshow function displays images P0210 : in the same window shows two images)
    2006-12-09 20:22:53下载
    积分:1
  • music
    在满足MUSIC算法的假设前提下,MUSIC算法可以精确的估计出信号的DOA(MUSIC algorithm to meet the assumptions, MUSIC algorithm can accurately estimate the signal DOA)
    2011-09-23 20:10:10下载
    积分:1
  • mRMR
    mRMR(最小冗余最大相关)的比较好的文档,可参考一下(mRMR (minimum redundancy maximum correlation) of good documentation, reference)
    2021-03-05 22:49:30下载
    积分:1
  • PolarLab
    its a nice toolbox for compressive sensing
    2013-07-11 20:12:35下载
    积分:1
  • impulsefrequecy-response-code
    the calculation of imp response from the frequecny response in power delay profiel calculations
    2013-12-06 19:39:46下载
    积分:1
  • exercise
    根据公式I(n-1)=(1-In)/n 令I11=0计算I1 到I10; 根据公式In=1-nI(n-1) 令I0=0.6321 计算I1到I7; 根据公式X2=a , 令a=2,计算X的值。(According to the formula I(n-1)=(1-In)/n ,set I11 equals zero,and count I1 to I10. According to the formula In=1-nI(n-1),set I11 equals zero,and count I1 to I10. According to the formula X square equals a ,set a equals two ,then calculate X )
    2010-05-09 21:54:01下载
    积分:1
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