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ofdm.m(B)
一个关于ofdm的MATLAB仿真源代码(OFDM MATLAB )
- 2009-12-10 20:57:11下载
- 积分:1
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guodufenge
该源码是针对一篇避免过度分割提出的一种新的分水岭算法,具体matlab源码,针对各个步骤都给出了具体分析,个人觉得对学习图像分割的有帮助。(The source is to avoid over-segmentation for a proposed a new watershed algorithm matlab source code specific for each step are given a specific analysis, personal feel to learn image segmentation help.)
- 2013-08-28 20:02:08下载
- 积分:1
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MATLAB-GUI-design
介绍matlab中GUI的学习知识,值得对于matlab有兴趣的爱好者参考学习,我也在学习当中,还不错(Introduced in GUI matlab learning knowledge, it is worth for matlab interested enthusiasts refer to learning, I am also learning, good)
- 2013-12-29 00:37:01下载
- 积分:1
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matlab-calculation
本资源中包含了在matlab环境中常用的基本算法程序,其中也有大量的例子进行说明。(This resource contains the environment in matlab basic algorithm commonly used procedures, which also has a large number of examples will be described.)
- 2013-11-18 21:59:29下载
- 积分:1
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Digital_filterin_code
MATLAB辅助设计数字滤波器源代码,QUATUS II 实现!(MATLAB-aided design of digital filter source code, QUATUS II implementation!)
- 2009-03-31 13:19:42下载
- 积分:1
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stbc5
almouti空时分组码matlab仿真实现,源码有点乱,望大家见谅(almouti space-time block codes matlab simulation implementation, source code a bit chaotic, hope you forgive me)
- 2009-11-09 19:06:34下载
- 积分:1
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emd_1
Earth Mover Distance
- 2009-05-11 03:34:42下载
- 积分:1
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slide-bearing
轴承热弹流计算程序,很好用。可以计算高端轴承。(thermal、elastic DEFORM and fulid model,solving reynold eqn)
- 2015-04-15 20:57:51下载
- 积分:1
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MATLAB
采用遗传算法对于加工问题的排序,使其最快.(The use of genetic algorithm to sort the problem for the processing to make it the fastest.)
- 2009-04-11 10:25:53下载
- 积分:1
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0
说明: 给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入.
输入:第一行两个正整数n(物品数)和C(容量)
第二行n个正整数n,表示物品价值
第三行n个正整数n,表示物品重量
输出:第一行表示总价值
第二行n个数(0/1),0表示物品不装入,1表示装入
例如,
输入:
5 10
6 3 5 4 6
2 2 6 5 4
输出
15
1 1 0 0 1
(Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)
- 2009-07-01 23:07:01下载
- 积分:1