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RobustControlofaRocket
matlab关于鲁棒控制的例子,设计一个Rocket,有源代码,和设计过程详解。是入门的好资料(matlab on the examples of robust control, the design of a Rocket, active code, and explain the design process. Is a good data entry)
- 2008-01-26 09:58:05下载
- 积分:1
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gpstoolbox3.01
gps的matlab仿真工具包version3.01,函数和处理方法非常全,不错的gps开发仿真工具(gps the matlab simulation toolkit version3.01, function and processing method is very full, good development of simulation tools gps)
- 2010-11-22 21:09:43下载
- 积分:1
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surf2dxf
将matlab中的三维数据导成autocad可读的dxf格式(The three-dimensional data matlab lead into autocad dxf readable format)
- 2020-06-30 21:20:02下载
- 积分:1
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APIT_CS-2003-06
传统的近似三角形内点测试( APIT),即近似三角形内点测试定位算法,广泛应用于静态节点定位.结合粒子滤波提出改进算法,将APIT算法推广到节点动态定位.(Traditional approximate point inside the triangle test (APIT), namely the approximate point within the triangle test positioning algorithm, widely used in the static node localization. Combined with particle filter algorithm is proposed to improve the APIT algorithm is extended to the node dynamic positioning.)
- 2013-12-23 15:42:22下载
- 积分:1
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fuzzy
matlab的模糊数学工具箱,帮您处理更多非二元问题(the Fuzzy toolbox of MATLAB)
- 2010-12-03 13:59:22下载
- 积分:1
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FDNC
有限差分法求解振动力学中瞬态响应问题
matlab编写的GUI程序( Finite Difference Numerical Computation (FDNC) Program For calculating response of transient vibration)
- 2010-06-18 23:27:29下载
- 积分:1
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0002SpecialFunctionCalculation
通过这些不仅能掌握数理方程中常用的特殊函数算法,而且还能熟练的使用MATLAB编程来实现这些算法。(These not only can grasp the mathematical equations used in the special function algorithms, but also skilled use of MATLAB programming to achieve these algorithms.)
- 2009-01-15 21:22:26下载
- 积分:1
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zhiwenshibie
指纹识别的matlab源码下载,非常实用的,希望大家喜欢(zhi wen shi bie yuan cheng xu)
- 2010-11-14 21:08:12下载
- 积分:1
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help1liang
化学计量学中用于分辨的HELP方法!目前是世界上最好的分辨方法!此上传为以可视化的软件!(chemical metrology used to distinguish between the methods HELP! At present the world is the best way to distinguish! Chn to this visualization software!)
- 2007-06-19 19:47:57下载
- 积分:1
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2DMaxima
在二维空间里有两个点A=(X1,Y1)和B=(X2,Y2),如果X1>X2并且Y1>Y2 ,我们认为A优于B,A是这个集合的最大极值点,在给定的二维空间里的N个点的集合S中,找出最大极值点。(In two-dimensional space, there are two points = A = (X1, Y1) and B (X2, Y2), if the X1 and Y1 > X2 > Y2, we think that A is superior to B, A is the biggest extreme value point of the set, in A given set of N points in the two-dimensional space S, find out the most extreme value point.)
- 2013-12-24 21:02:56下载
- 积分:1