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洗车模型，经典排队论，关于排队模型的相应说明含在压缩文件之中(Wash model, classical queuing theory, queuing models regarding the appropriate instructions included in the compressed file into)

对风电功率的预测 时间序列预测 卡尔曼滤波预测 (Prediction of wind power time series prediction Kalman filter prediction)

matlab 中梁的弯矩 剪力 变形 轴力图形 以及源程序(matlab in Beams Shear deformation and axial force graphic source)

说明：  救护车的报警程序，分别为1000Hz和800Hz.(Ambulance alarm procedures were 1000Hz and 800Hz.)

说明：  学习C调用Mathematica内核函数的一个例子,包括计算和图形接口.(Learning C calling Mathematica kernel functions with examples, including computing and graphics interfaces.)

09系分习题与解答，适合系统分析人员的学习资料和技术文档(Exercises and answers to sub-09 system is suitable for systematic analysis of the learning materials and technical documentation)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)

有关EMAIL的一些简单编程，大家可以参考下(about some simple email programming which can be refered.)

用MATLAB实现特定人的孤立词语音识别，包含完整程序(MATLAB implementation of speech recognition)

load flow in redial distribution network