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基于matalab的信道自适应均衡技术研究(Matalab based channel adaptive equalization technology research)

光滑比的检验，用于灰色预测模型的建立过程，如果数据达不到要求，就不能用来预测(to exam it whether smooth or not)

卫星移动通信系统的电子教材，解压后可见，研究学习卫星通信的人可以参考借鉴(Electronic textbooks satellite mobile communication system, unpacked visible satellite communications research study can be a reference for people)

遗传算法解决作业车间调度问题，这一M文件为遗传算子的交叉操作(Genetic algorithms to solve the job shop scheduling problem, the M-file for the genetic operators crossover operation)

Nivada之CUDA，加速Matlab运算的文档资料。(Nivada of CUDA, speed up the Matlab computing documentation.)

说明：  visual c++ 开发的MemFile的源代码， 喜欢的可以下(visual c MemFile development of the source code, like they can)

说明：  自适应网格划分通用程序包，美国伯克利大学开发。(Adaptive Mesh generic package, the United States developed at the University of Berkeley.)

Matlab教程第11章，编成与案例教学(Matlab Guide Chapter 11, compiled and Case Teaching)

This is the simulation of Photoshop magic wand effect of Matlab procedures for image segmentation

某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的方法来做比较复杂，可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊，多次模拟预测停泊情况，以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)