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14
说明: 《精通MTLAB最优化计算》第14章 遗传优化算法
源码(" The most proficient MTLAB Optimization" Chapter 14, genetic algorithm source code)
- 2011-04-18 21:54:30下载
- 积分:1
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zd
说明: 该程序是我研制的“基于ARM9的无线自动报靶系统”的MATLAB算法的仿真验证部分
该程序的主要功能是对靶纸上的靶点和靶环进行提取和计算,然后计算出靶点的环数。
程序里面有注释(The program that I developed ARM9-based wireless automatic reported target system MATLAB algorithm simulation part of the program s main function is to target the paper target and target ring extraction and calculation, and then calculate the target of ring a few. Procedures there are Notes)
- 2009-01-14 17:54:20下载
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attachments_2009_09_20
image zoomig in matlab
- 2009-10-15 14:07:13下载
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MMSELSA
minimum mean square estimator log spectral amplitude is an anhanced technique of the minimum mean square estimator developed by Ephraih and Malah in 1985.It is used for signal processing by improving the Signal to noise Ratio.
- 2010-10-15 00:36:17下载
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bestbarcode
说明: 这是一个非常好的MATLAB条形码识别程序,里面包含M程序,执行所需图片,可直接执行,对于研究条形码识别的有非常好的帮助(This is a very good program MATLAB bar code, which contains M program, the implementation of the necessary pictures, can direct the implementation of bar code identification for the study of very good help)
- 2010-04-21 22:01:17下载
- 积分:1
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kerrpicstep-1.2.tar
this is a program of matlab
- 2011-09-03 19:57:35下载
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photonic_crystal
采用平面波展开法模拟2维光子晶体的能带结构,FDTD法模拟2维光子晶体能量传输(used plane wave expansion method for simulation of two-dimensional photonic crystal structure of the band, FDTD simulation of two-dimensional photonic crystal energy transmission)
- 2021-04-27 10:18:44下载
- 积分:1
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hebb
a hebb algorithm for neural network
- 2010-10-11 12:28:14下载
- 积分:1
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calculatorGUIMA
用matlab制作的简单的GUI形式的计算器,可进行加减乘除运算,供GUI初学者参考!(Calculator)
- 2009-06-09 17:08:59下载
- 积分:1
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YTY_GA_Final
To find the largest fitness value and its location
寻找最大适应性及相应的位置!Population N=50;crossover bits=n/2 (half of bits of an individual) with random locations,mutation bits = 4 种群数 N=50,交换位数= n/2, 即个体位数的一半,且位置随机;
变异位数统一取为4;
Nc=20,28,36,44,individuals for crossover(交换的个数)。Nm=1,5,10,15, individuals for mutation(变异的个数)。(To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
- 2010-12-27 21:23:27下载
- 积分:1