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hafumanbianma
输入各个字符及对应出现的次数 ; 建立赫夫曼树并对各个字符进行编码 ;然后 对 输入 的 二进制 串进行 译码(Enter the various characters and the corresponding number of emerging establish Huffman tree and the various characters coding then enter strings of binary decoding)
- 2007-12-16 18:50:01下载
- 积分:1
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Match-Template
卡尔曼滤波不错的程序,很实用,大家好好研究一起分享一起进步吧(Kalman filtering good program, very practical, we make good progress in research to share with the Bar)
- 2010-01-12 19:39:11下载
- 积分:1
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bp_drag_new
对fluent默认的Syamlal drag law进行曳力修正,多相流模型中(drag modify model in fluent)
- 2013-12-14 11:52:06下载
- 积分:1
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BinarySearchSample
The file name it says everything.........
- 2010-01-04 17:53:00下载
- 积分:1
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DesktopAA
室内环境射线跟踪算法研究,室内反射点追踪的计算(Indoor environmental ray tracing algorithm to calculate the reflection point indoor track)
- 2014-02-23 20:59:54下载
- 积分:1
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GA
说明: 实用的遗传算法,用matlab编写,完美运行。(good as it is !you will have a wonderful feeling!)
- 2013-04-02 22:17:43下载
- 积分:1
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MATLABlearninformation
matlab 学习仿真资料,对于学习matlab仿真的很有帮助(matlab learn and emulate material)
- 2010-08-31 12:26:05下载
- 积分:1
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Intro_to_characters
This is intro to characters and it is for educational use only. Only for personal study.
- 2014-11-27 01:06:12下载
- 积分:1
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5
一道程序编译顺序的考题,涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的,这道题的重点在“fun((int)fun(a+c,b),a-c)) ”语句。
系统首先要确定最外层 fun()函数的实参,第一个参数的确定需要递归调用fun()函数(不妨称其为内层函数)。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
- 积分:1
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VC-and-Matlab-mixed-programming
VC++与Matlab混合编程的快速实现(VC++ and Matlab Fast Implementation of mixed programming)
- 2011-04-18 23:13:13下载
- 积分:1