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work
设计一M阶自适应回波抵消器,已u(n)作为系统输入,d(n)作为系统期望响应,其中d(n)中混有u(n)的回声,信号以8kHz采样,现要求回波抵消器可以消除16ms之内的回声(The design of a M-order adaptive echo cancellation, and have u (n) as the system input, d (n) as a system to respond to the expectations, in which d (n) in a mixture of u (n) of the echo signal to 8kHz sampling, are requirements 16ms echo cancellation device can be eliminated within the echo)
- 2008-12-11 10:42:15下载
- 积分:1
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Digitalsignalprocessing
Matlab下的数字信号处理示例
Matlab下的数字信号处理示例
Matlab下的数字信号处理示例(Digital signal processing under Matlab example of digital signal processing under Matlab example of digital signal processing under Matlab example)
- 2009-09-06 14:03:07下载
- 积分:1
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BSOcodeV1
头脑风暴优化算法,群体智能算法中新兴的一种(Brainstorming optimization algorithms, swarm intelligence algorithm emerging as a)
- 2013-11-26 19:02:36下载
- 积分:1
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OOP_Mathlab
一本在Matlab开发环境下,讲解面向对象的编程书籍。适合从事Matlab编程的朋友们。(a book that is suitable for the friends who want to research object oriented programming using Matlab.)
- 2009-12-02 02:07:51下载
- 积分:1
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FDTD-Capter3
Dennis M.Sullivan FDTD书后matlab程序 已经调试验证 第三章(Dennis M.Sullivan
matlab program using FDTD book
have been debug and verify)
- 2012-06-03 11:31:53下载
- 积分:1
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delay
Delay routines, using a pre-computed loops_per_jiffy value.
- 2014-09-19 10:58:58下载
- 积分:1
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Enhancei.m.tar
mat lab code for image enhancement
- 2012-11-28 21:09:13下载
- 积分:1
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Tx_Rx_modified_DFT_SOFDM_ber
说明: SC-FDMA基本功能仿真,可能比较简单,但是值得熟悉了解(SC-FDMA基本功能仿真)
- 2010-04-27 14:24:35下载
- 积分:1
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OpinionWEB.m
Solver for Deffuant-Weisbuch models
- 2013-01-10 21:44:04下载
- 积分:1
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rengongmianyi
a=load( q.txt )
width=input( 请输入窗宽 )
step=input( 请输入步长 )
m=length(a)
for i=1:floor((m-width)/step+1)
s(i,1:width)=a(1,1+(i-1)*step:width+(i-1)*step)
end
b=max(max(s))
M=s./b
Rs=input( 请输入本体集半径 )
nd=input( 请输入检测器数模 )
k=1
while k<=nd
d{k}=rand(1,width)
for i=1:floor((m-width)/step+1)
if (norm(d{k}-s(i,:)))^2<Rs
break
end
end
k=k+1
end
for j=1:nd
for i=1:floor((m-width)/step+1)
R(i)=(norm(d{j}-s(i,:)))^2(a = load (' q.txt' ) width = input (' Please enter the window width' ) step = input (' Enter step size' ) m = length (a) for i = 1: floor ((m-width)/step+1) s (i, 1: width) = a (1,1+ (i-1)* step: width+ (i-1)* step) end b = max (max (s)) M = s./b Rs = input (' Please enter the body set radius' ) nd = input (' Please enter the number of detector modules' ) k = 1 while k < = nd d {k} = rand (1, width) for i = 1: floor ((m-width)/step+1) if (norm (d {k}-s (i ,:)))^ 2 <Rs
break
end
end
k=k+1
end
for j=1:nd
for i=1:floor((m-width)/step+1)
R(i)=(norm(d{j}-s(i,:)))^2)
- 2011-05-21 16:46:49下载
- 积分:1