etd

设计一M阶自适应回波抵消器，已u(n)作为系统输入，d(n)作为系统期望响应，其中d(n)中混有u(n)的回声，信号以8kHz采样，现要求回波抵消器可以消除16ms之内的回声(The design of a M-order adaptive echo cancellation, and have u (n) as the system input, d (n) as a system to respond to the expectations, in which d (n) in a mixture of u (n) of the echo signal to 8kHz sampling, are requirements 16ms echo cancellation device can be eliminated within the echo)

Matlab下的数字信号处理示例 Matlab下的数字信号处理示例 Matlab下的数字信号处理示例(Digital signal processing under Matlab example of digital signal processing under Matlab example of digital signal processing under Matlab example)

头脑风暴优化算法，群体智能算法中新兴的一种(Brainstorming optimization algorithms, swarm intelligence algorithm emerging as a)

一本在Matlab开发环境下，讲解面向对象的编程书籍。适合从事Matlab编程的朋友们。(a book that is suitable for the friends who want to research object oriented programming using Matlab.)

Dennis M.Sullivan FDTD书后matlab程序 已经调试验证 第三章(Dennis M.Sullivan matlab program using FDTD book have been debug and verify)

Delay routines, using a pre-computed loops_per_jiffy value.

mat lab code for image enhancement

说明：  SC-FDMA基本功能仿真，可能比较简单，但是值得熟悉了解(SC-FDMA基本功能仿真)

Solver for Deffuant-Weisbuch models

a=load( q.txt ) width=input( 请输入窗宽 ) step=input( 请输入步长 ) m=length(a) for i=1:floor((m-width)/step+1) s(i,1:width)=a(1,1+(i-1)*step:width+(i-1)*step) end b=max(max(s)) M=s./b Rs=input( 请输入本体集半径 ) nd=input( 请输入检测器数模 ) k=1 while k<=nd d{k}=rand(1,width) for i=1:floor((m-width)/step+1) if (norm(d{k}-s(i,:)))^2<Rs break end end k=k+1 end for j=1:nd for i=1:floor((m-width)/step+1) R(i)=(norm(d{j}-s(i,:)))^2(a = load (' q.txt' ) width = input (' Please enter the window width' ) step = input (' Enter step size' ) m = length (a) for i = 1: floor ((m-width)/step+1) s (i, 1: width) = a (1,1+ (i-1)* step: width+ (i-1)* step) end b = max (max (s)) M = s./b Rs = input (' Please enter the body set radius' ) nd = input (' Please enter the number of detector modules' ) k = 1 while k < = nd d {k} = rand (1, width) for i = 1: floor ((m-width)/step+1) if (norm (d {k}-s (i ,:)))^ 2 <Rs break end end k=k+1 end for j=1:nd for i=1:floor((m-width)/step+1) R(i)=(norm(d{j}-s(i,:)))^2)