登录
首页 » C++ Builder » cdjsdx

cdjsdx

于 2011-11-28 发布 文件大小:1KB
0 216
下载积分: 1 下载次数: 2

代码说明:

  利用MATLAB中的GUI建立可视化窗口(Using MATLAB visualization in the GUI to create the window)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • Boost
    Boost库使用大全,每个函数的详细介绍,使用例子,是上手的Boost的必备教材(Boost library Guinness, detailed description of each function, usage examples, are essential materials to get started Boost)
    2014-09-01 17:25:02下载
    积分:1
  • FFT
    利用MATLAB对信号进行FFT处理,观察幅频响应和相频响应(FFT using MATLAB for signal processing, observed amplitude frequency response and phase frequency response)
    2014-11-17 21:39:46下载
    积分:1
  • matlabcPP
    matlab c++对接matlab c++对接(matlab c++)
    2014-02-05 22:24:21下载
    积分:1
  • matrik_class
    simple c++ matrik operation class use dynamic allocation memory
    2009-11-09 01:26:18下载
    积分:1
  • 11seed-particle-effect-source
    cocos2dx 11种粒子效果源码,cocos2dx 11 seed particle effect source(cocos2dx 11 seed particle effect source)
    2014-01-08 09:28:39下载
    积分:1
  • multiply2
    三元组表示的稀疏矩阵的加法,减法,乘法运算器-Triples express the sparse matrix of the adder, subtraction, multiplication device(ples express the sparse matrix of the adder, subtraction, multiplication devic)
    2015-01-06 20:51:44下载
    积分:1
  • 1
    说明:  这是一个用c++实现的程序,功能:熟悉Mallat 算法、Daubechies 小波的构造、样条小波的性质(err)
    2008-06-17 18:16:21下载
    积分:1
  • 0
    说明:  给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入. 输入:第一行两个正整数n(物品数)和C(容量) 第二行n个正整数n,表示物品价值 第三行n个正整数n,表示物品重量 输出:第一行表示总价值 第二行n个数(0/1),0表示物品不装入,1表示装入 例如, 输入: 5 10 6 3 5 4 6 2 2 6 5 4 输出 15 1 1 0 0 1 (Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)
    2009-07-01 23:07:01下载
    积分:1
  • LMS_test
    Hello everybody,I am MAO,I am studying Least mean square algorithm right now.
    2015-03-04 11:39:23下载
    积分:1
  • themethodofcreatPRBS
    说明:  产生伪随机序列的方法,C语言编写,调试通过。(Generate pseudo-random sequence, C languages, debugging through.)
    2008-10-18 13:53:52下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载