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costas-matlab
锁相环仿真,基于matlab的源代码,比较靠谱!(The phase-locked loop simulation matlab source code more reliable!)
- 2012-12-29 16:52:49下载
- 积分:1
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proj_toolbox
投影bb法,用于求解非线性无约束最优化问题。(projected bb algorithm)
- 2012-11-23 19:45:13下载
- 积分:1
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FIR
FIR滤波器的仿真和实现。包括matlab的仿真文件和基于VHDL语言的硬件实现代码。算法包括串行和并行两种。(Simulation and implementation of FIR filters. Including matlab simulation files and hardware implementation based on VHDL code. Including both serial and parallel algorithms.)
- 2015-04-07 16:34:57下载
- 积分:1
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pmsgjg
采用matlab对平面四杆机构进行运动分析,并输出图像.(Using MATLAB to analyse the motion of planar four bar mechanism, and the output image)
- 2014-01-29 01:44:08下载
- 积分:1
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SOURCE-MODEL-FOR-HARMONIC
说明: 通过对周期性电压电流波形的起始时间与其相应的各
次谐波分量初始相位之间的关系进行研究,指出谐波源的特
性可以由其在基波电压初相位为零时的特性所唯一确定(Periodic voltage and current waveforms on the start time of its corresponding harmonic component of the relationship between the initial phase of research, pointed out that the characteristics of harmonic sources can be its initial phase in the fundamental zero-voltage characteristics of the CD a definite)
- 2011-03-09 21:37:59下载
- 积分:1
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PWM_2
PWM 2 SIMULATION MODEL
- 2011-11-27 05:43:43下载
- 积分:1
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kalman
卡尔曼的程序,里面有个基础的卡尔曼程序还有一个图像跟踪的卡尔曼程序。(Kalman s procedure, which has a basic program and a picture of Kalman Kalman tracking procedures.)
- 2010-10-12 17:15:05下载
- 积分:1
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pi_n
piiii jeirafjorjg knfojojr lajfpopazf
- 2012-05-20 20:42:09下载
- 积分:1
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PCM-for-flow-in-porous-media
附件是一份PDF文档有关KL-PCM,概率配点法模拟,KL展开等随机模拟较好的一篇综述(Probabilistic collocation method for flow in porous media:
Comparisons with other stochastic methods)
- 2012-01-06 19:30:05下载
- 积分:1
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ScieCompLec6Q1
solve boundary value problem of
Cousera课程Scientific Computing的Lecture 6对应的Quiz中Question 1的求解程序。
求解常微分方程的边值问题。
y =-4y (y of Theory: y=0.5*sin(2x))
x∈[0,1]
BC: y(0) = 0 y (1) = cos(2).
(solve boundary value problem of Cousera course Scientific Computing' s Lecture 6 corresponds Quiz Question 1 in the solution process. Solving boundary value problems for ordinary differential equations. y' ' =-4y (y of Theory: y = 0.5* sin (2x)) x ∈ [0,1] BC: y (0) = 0 y ' (1) = cos (2).)
- 2013-05-22 12:47:54下载
- 积分:1