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ECSBL
说明: 该程序实现二叉树的遍历功能,能够打印出二叉树的节点(The program realization of the binary tree traversal function, is capable of printing out the binary tree node)
- 2008-11-13 15:50:49下载
- 积分:1
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text
输入N个点的坐标,判断这N个点能否构成一个凸多边形。(Enter the coordinates of N points, to determine whether the N points form a convex polygon.)
- 2011-12-13 09:43:42下载
- 积分:1
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link
实现链表的一些操作,方便进行遍历,查找等程序(Operation, convenient linked list traversal, the search procedure)
- 2013-05-01 11:49:22下载
- 积分:1
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tree
二叉树的先序遍历。采用递归实现。释放资源时用了后序遍历。(Preorder traversal of a binary tree. Recursive implementation. Release resources used after preorder.)
- 2013-07-09 13:39:31下载
- 积分:1
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Monkeys-and-peach
Monkeys and peach,Monkeys and peach(Monkeys and peach)
- 2013-09-01 22:06:42下载
- 积分:1
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最短路径c++语言
说明: 用从c++写的floyd最短路径算法,可以求邻接矩阵任意两点的最短路径。(from using c++ to write the Floyd shortest path algorithm, can help adjacency matrix arbitrary 2:00 Shortest Path.)
- 2020-09-20 14:07:55下载
- 积分:1
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sort-algorithm-validation
直接插入排序算法验证。
快速排序算法验证。
直接选择排序算法验证。
(Direct insertion sort algorithm validation. Quick sort algorithm validation. Direct selection sort algorithm validation.)
- 2013-04-22 19:18:54下载
- 积分:1
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PrintTheSchedule_DataStructure_Lab4
数据结构试验-打印输出计算机本科专业4年每学期的课表;C++实现;图的邻接表存储结构以及拓扑排序的基本思想(Data structure test- printout computer 4 years of undergraduate per semester timetables C++ achieve basic idea of the adjacency table storage structure and topological sorting)
- 2012-11-24 23:30:41下载
- 积分:1
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DoubleStack
数据结构基础内容,两栈共享空间,参考《大话数据结构》(Structural basis of data content, two stacks shared space, refer to Westward data structure )
- 2014-12-06 12:09:30下载
- 积分:1
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jose
约瑟夫环(约瑟夫问题)是一个数学的应用问题:已知n个人(以编号1,2,3...n分别表示)围坐在一张圆桌周围。从编号为k的人开始报数,数到m的那个人出列;他的下一个人又从1开始报数,数到m的那个人又出列;依此规律重复下去,直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1,最后结果+1即为原问题的解。
(Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)
- 2015-01-09 17:28:41下载
- 积分:1