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tudebianli
图的遍历问题 数据结构 C C++ 源码 课程设计
严蔚敏版的书(yrteryryer)
- 2010-05-08 09:24:06下载
- 积分:1
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ds3
单向链表的创建与操作
设单向链表中节点的数据域的数据类型为整型,编写函数实现以下操作:
(1)实现单向链表的创建(包括初始化)与输出操作,节点的个数及节点的数据由用户输入。
(源代码:ds3-1.c)
(2)查找给定的单链表中的第i个节点,并将其地址返回。若不存在第i个节点,则返回空地址。
(源代码:ds3-2.c)
(3)查找给定的单链表中值为n的节点,并将其地址返回。若不存在值为n的节点,则返回空地址。同时,还应通过参数传回该节点的序号。
(源代码:ds3-3.c)
(4)删除给定的单链表中的第i个节点,成功返回1,失败返回0。
(源代码:ds3-4.c)
(5)删除给定的单链表中值为n的节点,成功返回1,失败返回0。
(源代码:ds3-5.c)
(6)在给定的单链表的第i位上插入值为n的节点。
(源代码:ds3-6.c)
(7)在给定单链表的值为m的节点的前面插入一个值为n的节点。
(源代码:ds3-7.c)
(Creation and operation of a one-way linked list
Set up a one-way linked list data type node integer data fields , write a function to achieve the following:
( 1 ) achieve the creation of a one-way linked list ( including initialization ) and output operation , the number of nodes and node data entered by the user .
( Source : ds3-1.c)
( 2 ) Find a single list given in the i-th node and returns its address . Without the presence of the i-th node , returns an empty address.
( Source : ds3-2.c)
( 3 ) Find a given node in a given value of n single list , and return address . Without the presence of the value of n nodes , returns an empty address. Meanwhile, the number should be returned by the parameters of the node .
( Source : ds3-3.c)
( 4 ) Delete the given singly linked list in the i-th node , the successful return 1, else return 0 .
( Source : ds3-4.c)
( 5 ) to delete a single node in the list is given n , the successful return 1, else return 0 .
( Source : ds3-5.c)
( 6 ) )
- 2014-05-11 19:19:41下载
- 积分:1
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car
停车场管理系统 c语言实现
停车场拥有M个车位和一条进入停车场的便道,便道上最多停放N辆汽车。汽车要想进入车位,首先进入便道等候。若有空闲车位,则停车入位,否则在便道继续等候,直至有车位空出。若便道已经停满等候的汽车,后到达的汽车只能离开,选择其他停车场。设计一个停车场管理系统,模拟停车场的运作,并统计停车场的收入。(Parking Management System with M c language parking spaces and a sidewalk into the parking lot, parked up on the sidewalk N cars. To enter the car parking spaces, first into the pavement waiting. If free parking, the parking into place, or in the sidewalk to wait until the needed spot. If the sidewalk is already full of parked cars waiting, after the arrival of the vehicle to leave, choose a parking lot. Designing a car park management systems, simulation parking operations and parking revenue statistics.)
- 2011-08-21 21:55:11下载
- 积分:1
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xx
说明: 数据结构实验报告链表的操作,包括创建空链表、插入、删除节点等(Experimental Report list data structure operations, including creating an empty list, insert, delete nodes, etc.)
- 2009-11-25 08:36:26下载
- 积分:1
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eightqueen
利用數據結構中的棧,實現19世紀著名數學家高斯提出的八皇后問題(Stack data structure, to achieve the eight queens problem of the 19th century, the famous mathematician Gauss)
- 2012-10-23 08:30:21下载
- 积分:1
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Josephus(data_struct)
数据结构中基于约瑟夫环问题,用C++方式实现的。。。。。(Data structure based on Josephus problem with C++ a manner. . . . .)
- 2013-11-17 11:30:24下载
- 积分:1
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migong
迷宫问题,利用随机数自动生成迷宫,并自动进行探索。迷宫起点及终点由用户自己设定。(Maze problem, the use of random number automatically generated maze, and automatically explore. The starting point and end point of the maze is set by the user.
双语对照
)
- 2021-04-26 16:48:45下载
- 积分:1
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jose
约瑟夫环(约瑟夫问题)是一个数学的应用问题:已知n个人(以编号1,2,3...n分别表示)围坐在一张圆桌周围。从编号为k的人开始报数,数到m的那个人出列;他的下一个人又从1开始报数,数到m的那个人又出列;依此规律重复下去,直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1,最后结果+1即为原问题的解。
(Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)
- 2015-01-09 17:28:41下载
- 积分:1
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class
给定m个n维向量a , a , ,am 1 2 ,向量分类问题要求将相同的向量划分为同一类。试用
抽象数据类型表设计解向量分类问题的有效算法。(Given m a n-dimensional vector a, a,, am 1 2 )
- 2008-05-05 22:03:41下载
- 积分:1
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migong
迷宫算法,1代表可以通过,0代表墙壁,自动找寻路线(Maze algorithm, 1 can pass 0 for the walls, automatically find routes)
- 2011-06-11 17:13:39下载
- 积分:1