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ZMN-radar
利用ZMNL方法进行雷达杂波的仿真与模拟,生成具有瑞利分布(ZMNL method using radar cluttersimulation and modeling to generate a Rayleigh distribution
)
- 2011-05-20 16:54:52下载
- 积分:1
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linearizeabt_5deg_roll
Linearized model of quadrotor about a 5 degree roll angle.
- 2011-05-31 06:03:24下载
- 积分:1
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EMD-LMD_Denoising
EMD或者LMD的能量密度与其平均周期的乘积K值,当K值发生较大变化的时候,证实该分量为白噪声,可以剔除,将剩下的分量进行重构,达到去噪的目的。(The product of K EMD or LMD energy density and average cycle value when the K value was changed greatly, the component for white noise can be eliminated, the remaining components are reconstructed to achieve the purpose of de-noising.)
- 2021-03-25 16:09:14下载
- 积分:1
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imageregistration
本程序,对三维重建的结果调试已通过,得到很好的实验结果,方便大家学习。(This procedure, the results of three-dimensional reconstruction of debugging has passed, get a good result, we facilitate learning.)
- 2020-12-06 20:49:33下载
- 积分:1
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bp
说明: 用BP神经网络的初步级应用实现
电机故障诊断(BP neural network with the initial level of motor fault diagnosis applications)
- 2021-01-29 22:48:34下载
- 积分:1
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pmdft21
DFT算法仿真,采用matlab环境,非常实用,欢迎下载!(DFT algorithm simulation using matlab environment, very practical, welcome to download!)
- 2009-11-15 21:20:58下载
- 积分:1
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flightdesignprogramusingmatlab
说明: 飞机设计的相关程序,全机总体参数计算程序 ,全机气动曲线计算程序 ,机翼载荷分布计算程序,巡航状态纵向动稳定性计算程序
,横航向稳定性计算程序,平飞速度范围计算程序,螺旋桨特性计算程序
(program about flight design including most of problems in flight design)
- 2010-03-20 02:03:16下载
- 积分:1
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mod_lte_tota
performance of quantizer in lte
performance of quantizer in lte
performance of quantizer in lte performance of quantizer in lte
- 2012-06-23 01:29:51下载
- 积分:1
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jsm-1
说明: matlab中最优化函数fmincon 求解非线性规划问题(fmincon used to solve nonlinear programming problem)
- 2010-04-25 22:16:24下载
- 积分:1
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111
function pi = solve2(count,m,cc)
借助布冯投针实验 仿真求pi的值
pi=0
frq=0
randNo = binornd(1,cc,1,m)
pro=zeros(1,count)
for j=1:count
for i = 1:m
if randNo(1,i) == 1
frq = frq + 1
end
pro(i) = frq/i
end
pi = (2*m)/frq
pro(j) = pi
end
pro = pro,num =1:count
plot(num,pro) (function pi = solve2 (count, m, cc) to vote with Buffon needle experiment simulation find the value of pi pi = 0 frq = 0 randNo = binornd (1, cc, 1, m) pro = zeros (1, count) for j = 1: count for i = 1: m if randNo (1, i) == 1 frq = frq+ 1 end pro (i) = frq/i end pi = (2* m )/frq pro (j) = pi end pro = pro, num = 1: count plot (num, pro) )
- 2011-05-24 15:39:41下载
- 积分:1