登录
首页 » Others » chap4

chap4

于 2013-11-06 发布 文件大小:1775KB
0 213
下载积分: 1 下载次数: 4

代码说明:

  matlab图像处理实例详解——数字图像的运算(matlab image processing example explanation- digital image computing)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • Robust
    Robust control design for square signal in a transfer untion and show the behavior of the system
    2014-02-08 19:22:17下载
    积分:1
  • ls-svmlsb1.5
    说明:  最小二乘支持向量机(来自于互联网,本人测试过,好使)(Least squares support vector machine (from the Internet, I tested, so that))
    2011-03-15 15:49:50下载
    积分:1
  • tuxiangkaiqibihe
    使用matlab语言对图像进行开启闭合操作,使用有效(matlab language of opening or closing operation of the image)
    2011-05-16 10:32:46下载
    积分:1
  • tzdcsxnc
    BP智能输入法的预测算法的matlab代码,本程序根据训练好的网络文件 YJWTPU.mat预测新的数据文件,包括有点检测、线检测、Hough变换、temp算法、lrjMcDM测试原理展示等功能(BP intelligent input method of prediction algorithm matlab code, the procedure according to the trained network file prediction YJWTPU.mat new data Files, including bit detection, line detection, Hough transform, temp algorithm, lrjMcDM test principle display and other functions.)
    2016-02-01 07:01:12下载
    积分:1
  • PSO
    用粒子群算法(PSO)优化样本再拟合函数找出最大值(Using Particle Swarm Optimization (PSO) to find optimal maximum sample and then fitting function)
    2010-09-01 14:47:06下载
    积分:1
  • turbo
    Turbo编译码程序,实现turbo编码和译码!(Turbo encoding and decoding procedures, turbo encoding and decoding)
    2015-01-19 18:36:51下载
    积分:1
  • GSO
    gso原始代码,萤火虫的matlab代码(gso code,the matlab code of glowworm algorithm)
    2013-01-11 20:54:28下载
    积分:1
  • metal_reflection_meep
    在MIT的meep中,用来计算银表面的折射率和吸收率。用于FDTD算法。(Meep at MIT, the silver surface used to calculate the refractive index and absorption rate. For the FDTD algorithm.)
    2013-07-26 22:11:07下载
    积分:1
  • 1
    说明:  本程序实现LPP降维功能,用于多模态故障诊断中(This procedure realize the LPP dimension reduction function, used in multimodal fault diagnosis )
    2013-08-31 10:53:40下载
    积分:1
  • pi_method1
    Estimated number of Pi ( Method 1) how do we estimate Pi by simulation? In the simulation, you keep throwing darts at random onto the dartboard. All of the darts fall within the square, but not all of them fall within the circle. Here s the key. If you throw darts completely at random, this experiment estimate the ratio of the area of the circle to the area of the square, by counting the number of darts in each. Our study of the geometry tells us this ratio is Pi/4. So, now we can estimate Pi as
    2013-04-29 02:49:47下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载