Q-learning

varios demos para sistema de optimización de antenas

说明：  第6章 无约束一维极值问题 所在章节 函数名 功 能 6.1 minJT 用进退法求解一维函数的极值区间 6.2 minHJ 用黄金分割法求解一维函数的极值 6.3 minFBNQ 用斐波那契法求解一维函数的极值 6.4 minNewton 用牛顿法求解一维函数的极值 6.5 minGX 用割线法求解一维函数的极值 6.6 minPWX 用抛物线法求解一维函数的极值 6.7 minTri 用三次插值法求解一维函数的极值 6.8.1 minGS 用Goldstein法求解一维函数的极值 6.8.2 minWP 用Wolfe-Powell法求解一维函数的极值 (Chapter 6 unconstrained extremum problem one-dimensional sections of the functional 6.1 minJT function method for solving one-dimensional with the advance and retreat of the extreme range of 6.2 minHJ function of the golden section method using one-dimensional function of the extreme 6.3 minFBNQ use Fibonacci method one-dimensional function of the extreme 6.4 minNewton Newton method with one-dimensional function with extreme 6.5 minGX one-dimensional secant method to solve the extreme 6.6 minPWX function method for solving one-dimensional parabolic function of the extreme 6.7 minTri method with cubic interpolation one-dimensional function of the extreme 6.8.1 minGS Goldstein method with one-dimensional function of the extreme 6.8.2 minWP Wolfe-Powell method with a one-dimensional extreme value function)

dc load flow in power system. linear proggramming model use in dc power flow of power system.

ls ber performance OF OFDM CHANNEL WHICH shows why ls in ofdm is better than other.

电液比例液压系统模糊控制器的设计，模糊推理系统作用下电液比例控制系统进行阶跃响应(Electro-hydraulic proportional hydraulic system, fuzzy controller, fuzzy inference system under the effect of electro-hydraulic proportional control system step response)

Matlab source codes for a book: Quarteroni Saleri 2006 Scientific Computing with MATLAB and Octave

RS编码的例子，可以参考这个学RS编码,可以参考通信原理的书籍来对照来学！(This is a example about RS coding ,and you can learn RS by that.)

迫零和最小均方误差比较，非常好的程序，保证可以仿真出图形(DIP text book kmeans image segmentation Input: ima: grey color image k: Number of classes Output: mu: vector of class means mask:)

学习惯性导航仿真的好资料，分析以上程序，可以很好理解惯性导航系统的原理。(Learning the simulation data of inertial navigation)

依据两个点的经纬度计算这两点在地球上距离的函数文件，误差很小(Calculated based on latitude and longitude of two points on Earth from these two points in the function file, the error is small)